Explanation Given information: An equation of parabola is given as, y = x 2 + b x . Also, b changes from − ∞ to ∞ . Concepts used: 1. ) A standard quadratic equation y = a x 2 + b x + c , a ≠ 0 , represents a parabola and the solution of this quadratic is the point where parabola crosses x − axis. 2. ) If a > 0 then, parabola y = a x 2 + b x + c opens upward. 3. ) If a < 0 then, parabola y = a x 2 + b x + c opens downward. Calculation: An equation of parabola is given as, y = x 2 + b x . Solution of this quadratic equation will be given as, x = − b ± b 2 − 4 a c 2 a ⇒ x = − b ± b 2 − 4 a ( 0 ) 2

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

21st Edition

ISBN: 9781319438333

Author: Rogawski

Publisher: MAC HIGHER

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Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

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Chapter 1.2, Problem 8PQ

To determine

To describe:

The changes of parabolas y=x2+bx as b changes from −∞ to ∞.

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Chapter 1.2, Problem 7PQ

Chapter 1.2, Problem 1E

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Chapter 1 Solutions

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

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