Explanation Given information: f ( x ) = x 2 x 2 − 1 Concept used: One-to-One function: - A function f is one-to-one on a domain D if, for every value c, the equation f ( x ) = c has at most one solution for x ∈ D . Or, equivalently, if for all a , b ∈ D , if a ≠ b , then f ( a ) ≠ f ( b ) Inverse: - Let f have domain D and range R To determine (b) If f ( x ) = x 2 x 2 − 1 then find the inverse function for f in [ 0 , ∞ )

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

21st Edition

ISBN: 9781319438333

Author: Rogawski

Publisher: MAC HIGHER

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Limits

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Chapter 1.5, Problem 57E

To determine

(a)

Let f(x)=x2x2−1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [0,∞).

To determine

(b)

If f(x)=x2x2−1 then find the inverse function for f in [0,∞)

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Chapter 1.5, Problem 56E

Chapter 1.5, Problem 58E

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Evaluate the next integral

Chapter 1 Solutions

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

Ch. 1.1 - Prob. 1PQ Ch. 1.1 - Prob. 2PQ Ch. 1.1 - Prob. 3PQ Ch. 1.1 - Prob. 4PQ Ch. 1.1 - Prob. 5PQ Ch. 1.1 - Prob. 6PQ Ch. 1.1 - Prob. 7PQ Ch. 1.1 - Prob. 8PQ Ch. 1.1 - Prob. 9PQ Ch. 1.1 - Prob. 10PQ

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - 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(a) Let f ( x ) = x 2 x 2 − 1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [ 0 , ∞ ) .

Solution Summary: The author concludes that f is not one-to-one and therefore invertible.

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(a)

Let f(x)=x2x2−1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [0,∞).

(b)

If f(x)=x2x2−1 then find the inverse function for f in [0,∞)

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Chapter 1 Solutions

(a) Let f ( x ) = x 2 x 2 − 1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [ 0 , ∞ ) .

Solution Summary: The author concludes that f is not one-to-one and therefore invertible.

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(a) Let f(x)=x2x2−1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [0,∞).

(b) If f(x)=x2x2−1 then find the inverse function for f in [0,∞)

Want to see the full answer?

Chapter 1 Solutions

(a)

Let f(x)=x2x2−1 then explain why f is not invertible. Furthermore, explain why f is invertible if we restrict the domain to [0,∞).

(b)

If f(x)=x2x2−1 then find the inverse function for f in [0,∞)