The overall structures of molecular, network and amorphous solids differ each other has to be explained. Concept introduction: Molecular solid: Molecular solids melt closer to 300 °C, which is can be either ductile or brittle. Many molecular solids have a large band gap between the valence band and conduction band. Network solid: Network solid has very high melting point, which are very hard. Network solid doesn't conduct electricity, which are insoluble in water and organic solvents. Amorphous solid: In these solids particles are randomly arranged in three dimensions, does not have sharp melting points, which forms due to sudden cooling of liquid.
The overall structures of molecular, network and amorphous solids differ each other has to be explained. Concept introduction: Molecular solid: Molecular solids melt closer to 300 °C, which is can be either ductile or brittle. Many molecular solids have a large band gap between the valence band and conduction band. Network solid: Network solid has very high melting point, which are very hard. Network solid doesn't conduct electricity, which are insoluble in water and organic solvents. Amorphous solid: In these solids particles are randomly arranged in three dimensions, does not have sharp melting points, which forms due to sudden cooling of liquid.
Solution Summary: The author explains that the overall structures of molecular, network and amorphous solids differ each other.
The overall structures of molecular, network and amorphous solids differ each other has to be explained.
Concept introduction:
Molecular solid:
Molecular solids melt closer to 300 °C, which is can be either ductile or brittle. Many molecular solids have a large band gap between the valence band and conduction band.
Network solid:
Network solid has very high melting point, which are very hard.
Network solid doesn't conduct electricity, which are insoluble in water and organic solvents.
Amorphous solid:
In these solids particles are randomly arranged in three dimensions, does not have sharp melting points, which forms due to sudden cooling of liquid.
Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point
Chapter 12 Solutions
OWLv2 6-Months Printed Access Card for Kotz/Treichel/Townsend's Chemistry & Chemical Reactivity, 9th, 9th Edition
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