Physics Laboratory Manual
Physics Laboratory Manual
4th Edition
ISBN: 9781133950639
Author: David Loyd
Publisher: Cengage Learning
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Chapter 12, Problem 5PLA

A spring of spring constant k = 8.75 N/m is hung vertically from a rigid support. A mass of 0.500 kg is placed on the end of the spring and supported by hand at a point so that the displacement of the spring is 0.250 m. The mass is suddenly released and allowed to fall. At the lowest position of the mass what is the displacement of the spring from its equilibrium position? (Hint: Apply Equation 5 with x1 = 0.250 m and x2 the unknown. This will lead to a quadratic equation with one of the solutions the unknown x2 and the other solution the original 0.250 m displacement.) Show your work.

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A 0.25 kg mass is attached to a vertical spring. Suppose the spring has a force constant of 10 N/m and an equilibrium position of y=0 m when there is no mass attached. Where is the equilibrium position when the mass is hung from the spring? Assume downward is positive in y. (List answer in meters)
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= A block of mass m = 2.00 kg is attached to a spring of force constant k is pulled to a position x; = 4.05 cm to the right of equilibrium and released from rest. k x=0 m x = x₁ 590 N/m as shown in the figure below. The block (a) Find the speed the block has as it passes through equilibrium if the horizontal surface is frictionless. 0.696 m/s (b) Find the speed the block has as it passes through equilibrium (for the first time) if the coefficient of friction between block and surface is Mk = 0.350. 0.675 The force of friction causes an increase in the internal energy of the system and a decrease in the total mechanical energy. m/s
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