(a) Derive the polynomial of degree five that satisfies both the Legendre equation ( 1 − x 2 ) y ″ − 2 x y ′ + 30 y = 0 and the normalization condition y ( 1 ) = 1 . (b) Sketch your solution from (a) and determine approximations to all zeros and local maxima and local minima on the interval ( − 1 , 1 ) .
(a) Derive the polynomial of degree five that satisfies both the Legendre equation ( 1 − x 2 ) y ″ − 2 x y ′ + 30 y = 0 and the normalization condition y ( 1 ) = 1 . (b) Sketch your solution from (a) and determine approximations to all zeros and local maxima and local minima on the interval ( − 1 , 1 ) .
Solution Summary: The author explains how to find the polynomial of degree five that satisfies the Legendre equation.
(a) Derive the polynomial of degree five that satisfies both the Legendre equation
(
1
−
x
2
)
y
″
−
2
x
y
′
+
30
y
=
0
and the normalization condition
y
(
1
)
=
1
.
(b) Sketch your solution from (a) and determine approximations to all zeros and local maxima and local minima on the interval
(
−
1
,
1
)
.
Formula Formula A function f(x) attains a local maximum at x=a , if there exists a neighborhood (a−δ,a+δ) of a such that, f(x)<f(a), ∀ x∈(a−δ,a+δ),x≠a f(x)−f(a)<0, ∀ x∈(a−δ,a+δ),x≠a In such case, f(a) attains a local maximum value f(x) at x=a .
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
Chapter 1 Solutions
Differential Equations And Linear Algebra, Books A La Carte Edition (4th Edition)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.