One solution to the initial-value problem d y d x = 2 3 ( y − 1 ) 1 / 2 , y ( 1 ) = 1 is y ( x ) = 1 .Determine another solution to the initial-value problem. Does this contradict the existence and uniqueness theorem (Theorem 1.3.2)? Explain.
One solution to the initial-value problem d y d x = 2 3 ( y − 1 ) 1 / 2 , y ( 1 ) = 1 is y ( x ) = 1 .Determine another solution to the initial-value problem. Does this contradict the existence and uniqueness theorem (Theorem 1.3.2)? Explain.
Solution Summary: The author explains the existence and uniqueness theorem, which states that if there is f(x,y) be a function that is continuous on the rectangle R, there
is
y
(
x
)
=
1
.Determine another solution to the initial-value problem. Does this contradict the existence and uniqueness theorem (Theorem 1.3.2)? Explain.
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