Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
8th Edition
ISBN: 9781305367333
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 12, Problem 46CR
Interpretation Introduction

(a)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  1

Explanation of Solution

For H2 O

Part A Step 1 →

O 6H 1x2

Sum(total atoms) = 8

Step 2 →

Pair of electrons = 8/2 = 4 

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  2

Electron pairs for bonds = 2

Step 3 → Remaining electron pairs = 2

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  3

Step 2 → 4 electron pairs around O atom. So that electron pairs geometry around the O atom is tetrahedral.

Step 3 → But around the O atom,

No: of bonding pairs = 2

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  4

No: of non- bonding pairs = 2

Step 4 → Name of the structure = V-shaped or Bend.

Interpretation Introduction

(b)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

Explanation of Solution

For PH3 Part A Step 1 → P 5      

H 1x3   

Sum = 8

Step 2 → Pair of electrons = 8/2 = 4 

Electron pairs for bonds = 3

Step 3 → Remain electron pairs = 1

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  5

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  6

Step 2 → 4 electron pairs around P   atom. So that electron pairs geometry around the P   atom is tetrahedral.

Step 3 → But around the P   atom, No: of bonding pairs = 3

No: of non- bonding pairs = 1

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  7

Step 4 → Name of the structure = Trigonal pyramid.

Interpretation Introduction

(c)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

CBr4

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  8

Explanation of Solution

CBr4 Part A. Step 1 → C 4

Br 7x4

Sum = 32

Step 2 → Pair of electrons = 32/2 = 16 

Electron pairs for bonds = 4

Step 3 → Remain electron pairs = 12(3×4)

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  9

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  10

Step 2 → 4 electron pairs around C atom. So that electron pairs geometry around the C atom is tetrahedral.

Step 3 → But around the C atom, No: of bonding pairs = 4

No: of non- bonding pairs = 0

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  11

Step 4 → Name of the structure = Tetrahedral.

Interpretation Introduction

(d)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

ClO4 .

Explanation of Solution

For ClO4 -

Part A. Step 1 → Cl 7 

O 6x4

(1)   charge ( one more electron

Sum = 31+1= 32

Step 2 → Pair of electrons = 32/2 = 16

Electron pairs for bonds = 4

Step 3 → Remain electron pairs = 12(3×4)

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  12

Step 2 → 4 electron pairs around Cl atom. So that electron pairs geometry around the Cl atom is tetrahedral.

Step 3 → But around the Cl atom, No: of bonding pairs = 4

No: of non- bonding pairs = 0

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  13

Step 4 → Name of the structure = Tetrahedral

But considering resonance, the exact position of three p bonds cannot be determined exactly. It provides a p cloud over the molecule. So that a resonance hybrid determines the exact structure of ClO4 - molecule.

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  14

Interpretation Introduction

(e)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

BF3

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  15

Explanation of Solution

BF3

Part A. Step 1 → B 3 

F 7x3 

Sum = 24

Step 2 → Pair of electrons = 24/2 = 12 

Electron pairs for bonds = 3

Step 3 → Remain electron pairs = 9(3×3)  

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  16

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  17

Step 2 → 3  electron pairs around B atom. So that electron pairs geometry around the B atom is Trigonal planar.

Step 3 → Also around the B atom,

No: of bonding pairs = 3 

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  18

No: of non- bonding pairs = 0

Step 4 → Name of the structure = Trigonal planar.

Interpretation Introduction

(f)

Interpretation:

The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.

Concept Introduction:

Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.

When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Expert Solution
Check Mark

Answer to Problem 46CR

BeF2.

Explanation of Solution

BeF2

Part A. Step 1 → Be 2 

F 7×2  

Sum = 16

Step 2 → Pair of electrons = 16/2 = 8

Electron pairs for bonds = 2

Step 3 → Remain electron pairs = 6(3×2)    

Part B Step 1 → Lewis structure

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  19

Step 2 → 2 electron pairs around Be atom. So that electron pairs geometry around the Be atom is Linear.

Step 3 → Also around the Be atom, No: of bonding pairs = 3

No: of non- bonding pairs = 0

Step 4 → Name of the structure = Linear

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card, Chapter 12, Problem 46CR , additional homework tip  20.

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Chapter 12 Solutions

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card

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Are the molecules in...Ch. 12 - Prob. 3CRCh. 12 - Prob. 4CRCh. 12 - Prob. 5CRCh. 12 - hat is the enthalpy change for a process? Is...Ch. 12 - Prob. 7CRCh. 12 - Prob. 8CRCh. 12 - Prob. 9CRCh. 12 - What is a driving force? Name two common and...Ch. 12 - Prob. 11CRCh. 12 - Methane, CH4, is the major component of natural...Ch. 12 - What is electronegative radiation? Give some...Ch. 12 - Prob. 14CRCh. 12 - Do atoms in excited states emit radiation...Ch. 12 - Prob. 16CRCh. 12 - Schrodinger and de Broglie suggested a...Ch. 12 - Describe the general characteristics of the first...Ch. 12 - Prob. 19CRCh. 12 - Describe the sublevels and orbitals that...Ch. 12 - Describe electron spin. How does electron spin...Ch. 12 - Prob. 22CRCh. 12 - List the order in which the orbitals are filled as...Ch. 12 - Prob. 24CRCh. 12 - Prob. 25CRCh. 12 - Prob. 26CRCh. 12 - What are the representative elements? 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