Chemistry: A Molecular Approach (4th Edition)
Chemistry: A Molecular Approach (4th Edition)
4th Edition
ISBN: 9780134112831
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 12, Problem 45E
Interpretation Introduction

To determine: The formula of the oxide of titanium.

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The complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex. a) Identify if the [Cr(CN)6] anionic complex has 4 long and 2 short bonds (left side of figure) or if the complex has 4 short and 2 long bonds (right side of figure) with respect to Oh symmetry. Use crystal field theory to answer this question. Explain/rationalize your decision. Can the provided information decide on the order of orbital energies? Dah Tetragonal Distortion ய Dab z-compression z-elongation x and y elongation O symmetry x and y compression E eg d² dx²-y² t2g dxy dxz dyz Question 4 a) continued: Provide your explanations in the space below. b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc as well as the paramagnetic and…
a) Draw the octahedral mer-[FeCl3(CN)3] complex and determine its point group. Use proper wedges and dashes in order to illustrate 3 dimensional details. Use the point group to determine if the complex has a resulting net dipole moment and describe its allowed direction with respect to its symmetry elements (if applicable). ード M 4- b) Substitute one chlorido ligand in mer-[FeCl3(CN)3] 4 with one fluorido ligand. Determine all possible isomers and their corresponding point groups. Use the point groups to determine if the complexes have resulting net dipole moments and describe their allowed direction with respect to its symmetry elements (if applicable). The number of complex sketches below is not necessarily indicative of the number of isomers. 4- 4- ☐☐☐ c) Substitute two chlorido ligands in mer-[FeCl3 (CN)3] 4 with two fluorido ligands. Determine all possible isomers and their corresponding point groups.. Use the point groups to determine if the complexes have resulting net dipole…
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Chapter 12 Solutions

Chemistry: A Molecular Approach (4th Edition)

Ch. 12 - Prob. 11SAQCh. 12 - Prob. 12SAQCh. 12 - Prob. 13SAQCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - 37. Polonium crystallizes with a simple cubic...Ch. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - Prob. 61ECh. 12 - Prob. 62ECh. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - Prob. 65ECh. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - Prob. 68ECh. 12 - Prob. 69ECh. 12 - Prob. 70ECh. 12 - 71. One kind of polyester is a condensation...Ch. 12 - 72. Nomex, a condensation copolymer used by...Ch. 12 - Prob. 73ECh. 12 - Prob. 74ECh. 12 - Prob. 75ECh. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - Prob. 78ECh. 12 - Prob. 79ECh. 12 - 80. Consider the body-centered cubic structure...Ch. 12 - Prob. 81ECh. 12 - Prob. 82ECh. 12 - Prob. 83ECh. 12 - Prob. 84ECh. 12 - Prob. 85ECh. 12 - Prob. 86ECh. 12 - Prob. 87ECh. 12 - Prob. 88ECh. 12 - Prob. 89ECh. 12 - Prob. 90ECh. 12 - Prob. 91ECh. 12 - Prob. 92ECh. 12 - Prob. 93ECh. 12 - Prob. 94ECh. 12 - Prob. 95ECh. 12 - Prob. 96ECh. 12 - Prob. 97ECh. 12 - Prob. 98ECh. 12 - Prob. 99ECh. 12 - Prob. 100ECh. 12 - Prob. 101ECh. 12 - Prob. 102ECh. 12 - Prob. 103ECh. 12 - Prob. 104ECh. 12 - Prob. 105DIA
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