Chemistry: A Molecular Approach (4th Edition)
4th Edition
ISBN: 9780134112831
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 12, Problem 98E
Interpretation Introduction
To explain: The reason for the oil or glass to not interfere with the diffraction pattern of the crystal.
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The complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is
paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex.
a) Identify if the [Cr(CN)6] anionic complex has 4 long and
2 short bonds (left side of figure) or if the complex has 4
short and 2 long bonds (right side of figure) with respect
to Oh symmetry. Use crystal field theory to answer this
question. Explain/rationalize your decision. Can the
provided information decide on the order of orbital
energies?
Dah
Tetragonal Distortion
ய
Dab
z-compression
z-elongation
x and y elongation
O symmetry
x and y compression
E
eg d² dx²-y²
t2g
dxy dxz dyz
Question 4 a) continued:
Provide your explanations in the space below.
b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic
phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc
as well as the paramagnetic and…
a) Draw the octahedral mer-[FeCl3(CN)3] complex and determine its point group. Use proper wedges and
dashes in order to illustrate 3 dimensional details. Use the point group to determine if the complex has a
resulting net dipole moment and describe its allowed direction with respect to its symmetry elements (if
applicable).
ード
M
4-
b) Substitute one chlorido ligand in mer-[FeCl3(CN)3] 4 with one fluorido ligand. Determine all possible
isomers and their corresponding point groups. Use the point groups to determine if the complexes have
resulting net dipole moments and describe their allowed direction with respect to its symmetry elements (if
applicable). The number of complex sketches below is not necessarily indicative of the number of isomers.
4-
4-
☐☐☐
c) Substitute two chlorido ligands in mer-[FeCl3 (CN)3] 4 with two fluorido ligands. Determine all possible
isomers and their corresponding point groups.. Use the point groups to determine if the complexes have
resulting net dipole…
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Chapter 12 Solutions
Chemistry: A Molecular Approach (4th Edition)
Ch. 12 - Prob. 1SAQCh. 12 - Prob. 2SAQCh. 12 - Prob. 3SAQCh. 12 - Prob. 4SAQCh. 12 - Prob. 5SAQCh. 12 - Prob. 6SAQCh. 12 - Prob. 7SAQCh. 12 - Q8. Which solid has the highest melting point?
a)...Ch. 12 - Prob. 9SAQCh. 12 - Prob. 10SAQ
Ch. 12 - Prob. 11SAQCh. 12 - Prob. 12SAQCh. 12 - Prob. 13SAQCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - 37. Polonium crystallizes with a simple cubic...Ch. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - Prob. 61ECh. 12 - Prob. 62ECh. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - Prob. 65ECh. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - Prob. 68ECh. 12 - Prob. 69ECh. 12 - Prob. 70ECh. 12 - 71. One kind of polyester is a condensation...Ch. 12 - 72. Nomex, a condensation copolymer used by...Ch. 12 - Prob. 73ECh. 12 - Prob. 74ECh. 12 - Prob. 75ECh. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - Prob. 78ECh. 12 - Prob. 79ECh. 12 - 80. Consider the body-centered cubic structure...Ch. 12 - Prob. 81ECh. 12 - Prob. 82ECh. 12 - Prob. 83ECh. 12 - Prob. 84ECh. 12 - Prob. 85ECh. 12 - Prob. 86ECh. 12 - Prob. 87ECh. 12 - Prob. 88ECh. 12 - Prob. 89ECh. 12 - Prob. 90ECh. 12 - Prob. 91ECh. 12 - Prob. 92ECh. 12 - Prob. 93ECh. 12 - Prob. 94ECh. 12 - Prob. 95ECh. 12 - Prob. 96ECh. 12 - Prob. 97ECh. 12 - Prob. 98ECh. 12 - Prob. 99ECh. 12 - Prob. 100ECh. 12 - Prob. 101ECh. 12 - Prob. 102ECh. 12 - Prob. 103ECh. 12 - Prob. 104ECh. 12 - Prob. 105DIA
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