To find the product and mechanism of the reactions by lithium aluminum hydride. Concept introduction: Hydride reacts with the carbonyl group, C = O of aldehydes or ketones to give alcohols. LiAlH 4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

Question

Want to see the full answer?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²

K for each reaction step. Be sure to account for all bond-breaking and bond-making steps. HI HaC Drawing Arrows! H3C OCH3 H 4 59°F Mostly sunny H CH3 HO O CH3 'C' CH3 Select to Add Arrows CH3 1 L H&C. OCH3 H H H H Select to Add Arrows Q Search Problem 30 of 20 H. H3C + :0: H CH3 CH3 20 H2C Undo Reset Done DELL

Draw the principal organic product of the following reaction.

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Answer 6

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

Answer 7

Chapter 12, Problem 44PP

(a)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by lithium aluminum hydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O of aldehydes or ketones to give alcohols.

LiAlH4 is a reducing agent which can reduce up to alcohol only. It can't reduce any compounds to alkanes. It is more reactive than sodium borohydride.

Answer 8

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Answer 9

(b)

Interpretation Introduction

Interpretation: To find the product and mechanism of the reactions by sodium borohydride.

Concept introduction:

Hydride reacts with the carbonyl group, C=O , of aldehydes or ketones to give alcohols.

Sodium borohydride is comparatively less reactive in comparison to lithium aluminum hydride. It easily reduces aldehydes and ketones and converts them into alcohols effectively. Acids, nitriles, esters, and amides are mostly unaffected. When interacting with halides and epoxides, it can also act as a nucleophile.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 12.1 - Prob. 1LTS Ch. 12.1 - Prob. 1PTS Ch. 12.1 - Prob. 2ATS Ch. 12.1 - Prob. 3CC Ch. 12.2 - Prob. 4CC Ch. 12.3 - Prob. 8CC Ch. 12.3 - Prob. 9CC Ch. 12.4 - Prob. 3LTS Ch. 12.4 - Prob. 10PTS Ch. 12.4 - Prob. 11ATS

Solution Summary: The author explains that lithium aluminum hydride reacts with the carbonyl group of aldehydes or ketones to give alcohols.

Concept explainers

Videos

Want to see the full answer?

Chapter 12 Solutions