Program Explanation Given information: The speed of the spacecraft that free falls toward the surface of the moon is 1000 mph and the deceleration of 20000 mi/h 2 . Calculation: The velocity can be expressed as, v ( t ) = a t + v 0 ....... (1) The position function can be expressed as, y ( t ) = 1 2 a t 2 + v 0 t + y 0 ....... (2) Here, a is the acceleration, v 0 is the initial velocity and y 0 is the initial position. The spacecraft is falling. Therefore, the velocity is negative. The speed of the spacecraft that free falls toward the surface of the moon is 1000 mph Therefore, the initial velocity is v 0 = − 1000 . Now, substitute 20000 for a and − 1000 for v 0 in equation (1) as, v ( t ) = 20000 t − 1000 ....... (3) Now, substitute 20000 for a and − 1000 for v 0 in equation (2) as, y ( t ) = 1 2 ⋅ 20000 ⋅ t 2 − 1000 t + y 0 The velocity of the spacecraft would be 0 when the spacecraft stops

5th Edition

ISBN: 9780321974235

Author: Calvis

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Longest Common Subsequence

The Longest Common Subsequence (LCS) is defined as the longest subsequence that is shared by all of the given sequences, assuming that the subsequence's elements do not have to be in consecutive locations in the original sequences. It is used in the area…

Question

Chapter 1.2, Problem 42P

Program Plan Intro

To calculate: The height above the lunar surfaces that the astronauts fire the retrorockets.

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Chapter 1.2, Problem 41P

Chapter 1.2, Problem 43P

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The height above the lunar surfaces that the astronauts fire the retrorockets.

Solution Summary: The author calculates the height above the lunar surfaces that the astronauts fire the retrorockets.

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To calculate: The height above the lunar surfaces that the astronauts fire the retrorockets.

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Chapter 1 Solutions