Program Explanation Given information: The initial velocity of the car is v 0 = 88 ft/s and the final velocity of the car is v = 0 ft/s and the car skids 176 ft after its breaks. Concept used: The differential equation d y d x = f ( x ) g ( y ) can be calculated with the help of separating the variables as, ∫ d y g ( y ) = ∫ f ( x ) d x Calculation: Consider x ( t ) as the position function. The function v ( t ) represents the velocity function. The velocity function can be written as, v ( t ) = v 0 + a t Here, a is the acceleration and v 0 is the initial velocity. The deceleration is the negative value of acceleration. Therefore, the velocity function can be written as, v ( t ) = v 0 − a t ....... (1) The initial velocity of the car is v 0 = 88 ft/s and the final velocity of the car is v = 0 ft/s and the car skids 176 ft after its breaks. Now substitute 88 for v 0 and 0 for v ( t ) in equation (1) to obtain the value of a t . 0 = 88 − a t a t = 88 The position function can be written as, x ( t ) = 1 2 a t 2 + v 0 t

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Chapter 1.2, Problem 30P

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To calculate: The deceleration of the car and the duration of time when the skid continues and the deceleration.

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Chapter 1.2, Problem 29P

Chapter 1.2, Problem 31P

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Chapter 1 Solutions

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The deceleration of the car and the duration of time when the skid continues and the deceleration.

Solution Summary: The author calculates the deceleration of the car and the duration of time when the skid continues.

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To calculate: The deceleration of the car and the duration of time when the skid continues and the deceleration.

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Chapter 1 Solutions