Explanation The differential equation is d y d x = 2 y x . In order to obtain the particular solution of the differential equation, first find general solution. That is separate the variables and integrate both sides. d y 2 y = 1 x d x ∫ d y 2 y = ∫ 1 x d x 1 2 log y = log x + log a log y = 2 log x + 2 log a On further simplification, log y = log x 2 + log a 2 log y = log ( C x 2 ) ( ∵ C = a 2 ) y = C x 2 Hence, the general solution of the differential equation is y = C x 2 . In order to obtain the particular solution, first find the value of C

COLL.MATH F/BUS ECO.(LL+18 WEEK MYLAB E)

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Author: Barnett

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Chapter 12, Problem 35RE

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To find: The particular solution of the differential equation dydx=2yx that passes through (2,1) and (−2,−1).

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Chapter 12, Problem 34RE

Chapter 12, Problem 36RE

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Chapter 12 Solutions

COLL.MATH F/BUS ECO.(LL+18 WEEK MYLAB E)

Ch. 12.1 - Matched Problem 1 Note that Find all...Ch. 12.1 - Prob. 2MP Ch. 12.1 - Prob. 3MP Ch. 12.1 - Prob. 4MP Ch. 12.1 - Prob. 5MP Ch. 12.1 - Prob. 6MP Ch. 12.1 - Prob. 1ED Ch. 12.1 - Prob. 1E Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E

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The particular solution of the differential equation d y d x = 2 y x that passes through ( 2 , 1 ) and ( − 2 , − 1 ) .

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To find: The particular solution of the differential equation dydx=2yx that passes through (2,1) and (−2,−1).

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Chapter 12 Solutions