Concept explainers
(a)
Interpretation: The number of rings and number of pi bonds in A is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
(b)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
(c)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
ORG CHEM CONNECT CARD
- Identify A–J:arrow_forwardBromo cyclopentadiene reacts to form a Witting Reagent (A), but does not react with aldehydes or ketones to give an alkene. Draw A and explain why it does not react with a carbonyl. Br 1. PPh3 2. Base A R H No Rxarrow_forwardCompound A exhibits a peak in its 1H NMR spectrum at 7.6 ppm, indicating that it is aromatic. (a) How are the carbon atoms of the triple bonds hybridized? (b) In what type of orbitals are the π electrons of the triple bonds contained? (c) How many π electrons are delocalized around the ring in A?arrow_forward
- Q.2 charrow_forward10. Consider the hydrogenation reaction of compound X to Y: H₂, Pt X (C8H14) →Y (C8H16) 25°C One can conclude that X has: A) no rings and no double bonds. B) no rings and one double bond. C) one ring and one double bond. D) two rings and no double bonds. E) one triple bond.arrow_forwardRank the compounds in each group in order of increasing boiling point. a. CH3(CH2)4I, CH3(CH2)sI, CH3(CH)gI b. CH;CH,CH,NH2, (CH3);N, CH3CH2CH,CH3 c. (CHa),COC(CH3)3, CHa(CH2)30(CH)¿CH3, CH3(CH2);OH COH d. HO. Br е. OH f.arrow_forward
- Four isomers A-D with the formula C5H12O exhibit different reactivity patterns as indicated below. Isomer A reacts with PCC and CrO3 to provide identical products. Isomer B reacts with PCC and CrO3 to provide different products. Isomers C and D do not react with either PCC or CrO3. Isomers A, B, and C readily react with NaH but D does not show any reactivity with NaH. The 1H NMR splitting patterns for these isomers are as follows. Isomer A: δ 0.91 (d, 3H), 0.90 (d, 3H), 1.18 (d, 3H), 1.92 (dqq, 1H), 3.38 (dq, 1H), 3.58 (bs, 1H). Isomer B: δ 1.25 (s, 9H), 3.45 (s, 2H), 3.65 (bs, 1H). Isomer C: δ 0.90 (t, 3H), 1.44 (q, 2H), 1.24 (s, 6H), 3.65 (bs, 1H). Isomer D: δ 1.10 (t, 3H), 1.13 (d, 6H), 3.19 (septet, 1H), 3.50 (q, 2H). Based on all of this information, provide the structures of A-D. (Note: If there is a chiral center on any of these molecules, assume the stereochemistry as “R”. dqq=doublet of a quartet of a quartet, bs=broad singlet)arrow_forwardQl- Arrange the following carbonium ion as more stable. Why? Me Me „Me A C Q2- Choose the substituted group that makes the following reaction faster. Why? X- CH2 H X- ососн, OR COOCH} Y= NH2 OR NO2 Q3- Which of the following compounds give the highest yield when reacting with a carbonyl compound. Why? NH 2 NH2 NH2 Me Me Me OR OR NO 2 NO2 NO2arrow_forward9.arrow_forward