Determine a solution to the differential equation ( 1 − x 2 ) y ″ − x y ′ + 4 y = 0 Of the form y ( x ) = a 0 + a 1 x + a 2 x 2 satisfying the normalization condition y ( 1 ) = 1 .
Determine a solution to the differential equation ( 1 − x 2 ) y ″ − x y ′ + 4 y = 0 Of the form y ( x ) = a 0 + a 1 x + a 2 x 2 satisfying the normalization condition y ( 1 ) = 1 .
Of the form
y
(
x
)
=
a
0
+
a
1
x
+
a
2
x
2
satisfying the normalization condition
y
(
1
)
=
1
.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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