For Problems 28–32, show that the given relation defines an implicit solution to the given differential equation, where c is an arbitrary constant. e y / x + x y 2 − x = c , y ′ = x 2 ( 1 − y 2 ) + y e y / x x ( e y / x + 2 x 2 y ) .
For Problems 28–32, show that the given relation defines an implicit solution to the given differential equation, where c is an arbitrary constant. e y / x + x y 2 − x = c , y ′ = x 2 ( 1 − y 2 ) + y e y / x x ( e y / x + 2 x 2 y ) .
Solution Summary: The author explains the differentiation law for the exponential function is given by ey/x-x=c, and the product law in differentiation.
For Problems 28–32, show that the given relation defines an implicit solution to the given differential equation, where c is an arbitrary constant.
e
y
/
x
+
x
y
2
−
x
=
c
,
y
′
=
x
2
(
1
−
y
2
)
+
y
e
y
/
x
x
(
e
y
/
x
+
2
x
2
y
)
.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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