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A transformation of data values by means of some mathematical or 1/x, can often yield a set of numbers that has “nicer" statistical properties than the original data. In particular, it may be possible to find a function for which the histogram of transformed values is more symmetric (or, even better, more like a bell-shaped curve) than the original data. As an example, the article “Time Lapse Cinematographic Analysis of Beryllium-Lung Fibroblast Interactions” (Environ. Research, 1983: 34-43) reported the results of experiments designed to study the behavior of certain individual cells that had been exposed to beryllium. An important characteristic of such an individual cell is its interdivision time (IDT). IDTs were determined for a large number of cells, both in exposed (treatment) and unexposed (control) conditions. The authors of the article used a logarithmic transformation, that is, transformed value = log(original value). Consider the following representative IDT data:
IDT | log10(IDT) | IDT log10(IDT) | IDT | log10(IDT) |
28.1 | 1.45 | 60.1 1.78 | 21.0 | 1.32 |
31.2 | 1.49 | 23.7 1.37 | 22.3 | 1.35 |
13.7 | 1.14 | 18.6 1.27 | 15.5 | 1.19 |
46.0 | 1.66 | 21.4 1.33 | 36.3 | 1.56 |
25.8 | 1.41 | 26.6 1.42 | 19.1 | 1.28 |
16.8 | 1.23 | 26.2 1.42 | 38.4 | 1.58 |
34.8 | 1.54 | 32.0 1.51 | 72.8 | 1.86 |
62.3 | 1.79 | 43.5 1.64 | 48.9 | 1.69 |
28.0 | 1.45 | 17.4 1.24 | 21.4 | 1.33 |
17.9 | 1.25 | 38.8 1.59 | 20.7 | 1.32 |
19.5 | 1.29 | 30.6 1.49 | 57.3 | 1.76 |
21.1 | 1.32 | 55.6 1.75 | 40.9 | 1.61 |
31.9 | 1.50 | 25.5 1.41 | ||
28.9 | 1.46 | 52.1 1.72 |
Use class intervals 10−<20, 20−<30, ... to construct a histogram of the original data. Use intervals 1.1−<1.2, 1.2−<1.3, ... to do the same for the transformed data. What is the effect of the transformation?
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Chapter 1 Solutions
Bundle: Probability and Statistics for Engineering and the Sciences, 9th + WebAssign Printed Access Card for Devore's Probability and Statistics for ... and the Sciences, 9th Edition, Single-Term
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- A survey of 581 citizens found that 313 of them favor a new bill introduced by the city. We want to find a 95% confidence interval for the true proportion of the population who favor the bill. What is the lower limit of the interval? Enter the result as a decimal rounded to 3 decimal digits. Your Answer:arrow_forwardA survey of 581 citizens found that 313 of them favor a new bill introduced by the city. We want to find a 95% confidence interval for the true proportion of the population who favor the bill. What is the lower limit of the interval? Enter the result as a decimal rounded to 3 decimal digits. Your Answer:arrow_forward2. The SMSA data consisting of 141 observations on 10 variables is fitted by the model below: 1 y = Bo+B1x4 + ẞ2x6 + ẞ3x8 + √1X4X8 + V2X6X8 + €. See Question 2, Tutorial 3 for the meaning of the variables in the above model. The following results are obtained: Estimate Std. Error t value Pr(>|t|) (Intercept) 1.302e+03 4.320e+02 3.015 0.00307 x4 x6 x8 x4:x8 x6:x8 -1.442e+02 2.056e+01 -7.013 1.02e-10 6.340e-01 6.099e+00 0.104 0.91737 -9.455e-02 5.802e-02 -1.630 0.10550 2.882e-02 2.589e-03 11.132 1.673e-03 7.215e-04 2.319 F) x4 1 3486722 3486722 17.9286 4.214e-05 x6 1 14595537 x8 x4:x8 x6:x8 1 132.4836 < 2.2e-16 1045693 194478 5.3769 0.02191 1 1198603043 1198603043 6163.1900 < 2.2e-16 1 25765100 25765100 1045693 Residuals 135 26254490 Estimated variance matrix (Intercept) x4 x6 x8 x4:x8 x6:x8 (Intercept) x4 x6 x8 x4:x8 x6:x8 0.18875694 1.866030e+05 -5.931735e+03 -2.322825e+03 -16.25142055 0.57188953 -5.931735e+03 4.228816e+02 3.160915e+01 0.61621781 -0.03608028 -0.00445013 -2.322825e+03…arrow_forward
- In some applications the distribution of a discrete RV, X resembles the Poisson distribution except that 0 is not a possible value of X. Consider such a RV with PMF where 1 > 0 is a parameter, and c is a constant. (a) Find the expression of c in terms of 1. (b) Find E(X). (Hint: You can use the fact that, if Y ~ Poisson(1), the E(Y) = 1.)arrow_forwardSuppose that X ~Bin(n,p). Show that E[(1 - p)] = (1-p²)".arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward
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