Mathematical Ideas (13th Edition) - Standalone book
Mathematical Ideas (13th Edition) - Standalone book
13th Edition
ISBN: 9780321977076
Author: Charles D. Miller, Vern E. Heeren, John Hornsby, Christopher Heeren
Publisher: PEARSON
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Chapter 12, Problem 1T

Visits to Social Networking Sites The table shows the number of persons age 2 and older in any U.S. location, in millions, who visited the listed Web sites at least once in June 2013.

Rank Web Site Visitors
1 Facebook 144.7
2 LinkedIn 50.6
3 Twitter 39.1
4 Tumblr 35.9
5 Pinterest 27.9
Source: com Score Media Metrix; com Score q Search

Use this information to determine each of the following.

(a) the mean number of visitors per site

(b) the range

(c) the standard deviation

(d) the coefficient of variation

(a)

Expert Solution
Check Mark
To determine

To calculate: The Mean number of visitors per site using the following information.

Rank Web Site Visitor
1 Facebook 144.7
2 LinkedIn 50.6
3 Twitter 39.1
4 Tumblr 35.9
5 Pinterest 27.9

Answer to Problem 1T

Solution:

The required mean is approximately 59.6 million

Explanation of Solution

Formula used:

Mean of n data items  can be found with the formula, x¯=xn

Calculation:

Since, mean can be found with the formula, x¯=xn

Thus, mean will be:

x¯=144.7+50.6+39.1+35.9+27.9559.6

(b)

Expert Solution
Check Mark
To determine

To calculate: The range of the following data.

Rank Web Site Visitor
1 Facebook 144.7
2 LinkedIn 50.6
3 Twitter 39.1
4 Tumblr 35.9
5 Pinterest 27.9

Answer to Problem 1T

Solution:

The required range is 116.8 million.

Explanation of Solution

Formula used:

Range is the difference between highest data value and lowest data value.

Calculation:

Since, range is the difference between highest data value and lowest data value

So, range =144.727.9=116.8

(c)

Expert Solution
Check Mark
To determine

To calculate: The standard deviation of the following data.

Rank Web Site Visitor
1 Facebook 144.7
2 LinkedIn 50.6
3 Twitter 39.1
4 Tumblr 35.9
5 Pinterest 27.9

Answer to Problem 1T

Solution:

The required standard deviation is 48.2 million.

Explanation of Solution

Formula used:

Standard deviation is:

s=(xix¯)2n1, where xi is the data value and x¯ is mean

Calculation:

Formula for standard deviation is:

s=(xix¯)2n1, where xi is the data value and x¯ is mean

Thus,

s=(144.759.6)2+(50.659.6)2+(39.159.6)2+(35.959.6)2+(27.959.6)2n1=7242.0+81.0+420.3+561.7+1004.951=9309.94=2327.5

Now, take the square root,

s=2327.548.2 million

(d)

Expert Solution
Check Mark
To determine

To calculate: The coefficient of variation of the following data.

Answer to Problem 1T

Solution:

The coefficient of variation is approximately 80.9%.

Explanation of Solution

Formula used:

Formula for coefficient of variation is:

V=sx¯×100, where s is standard deviation, x¯ is mean.

Calculation:

V=48.259.6×10080.9%

Hence, the coefficient of variation is approximately 80.9%.

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Chapter 12 Solutions

Mathematical Ideas (13th Edition) - Standalone book

Ch. 12.1 - Federal Revenue and Spending The graph shows U.S....Ch. 12.1 - Federal Revenue and Spending The graph shows U.S....Ch. 12.1 - Federal Revenue and Spending The graph shows U.S....Ch. 12.1 - Federal Revenue and Spending The graph shows U.S....Ch. 12.1 - Prob. 15ECh. 12.1 - Refer to the above graphs for Exercises 16-20....Ch. 12.1 - Prob. 17ECh. 12.1 - Refer to the above graphs for Exercises 16-20....Ch. 12.1 - Prob. 19ECh. 12.1 - Refer to the above graphs for Exercises 16-20....Ch. 12.1 - Reading a Circle Graph of Job-Training Sources The...Ch. 12.1 - Reading a Circle Graph of Job-Training Sources The...Ch. 12.1 - Prob. 23ECh. 12.1 - Correspondence between Education and Earnings Data...Ch. 12.1 - Prob. 25ECh. 12.1 - Net Worth of Retirement Savings Saura, wishing to...Ch. 12.1 - Prob. 27ECh. 12.1 - Net Worth of Retirement Savings Saura, wishing to...Ch. 12.1 - Prob. 29ECh. 12.1 - Sample Masses in a Geology Laboratory...Ch. 12.1 - Sample Masses in a Geology Laboratory...Ch. 12.1 - Record Temperatures According to the National...Ch. 12.1 - Prob. 33ECh. 12.1 - Frequencies and Probabilities of letter Occurrence...Ch. 12.1 - Prob. 35ECh. 12.1 - Prob. 36ECh. 12.1 - 37. 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