Concept explainers
To review:
The important considerations while designing a strategy to select mutants.
Introduction:
The technique used for identification and selection of individuals having a specific mutantÂ
![Check Mark](/static/check-mark.png)
Explanation of Solution
The important points to remember for designing a mutant selection strategy are as follows:
1. The strategy used should select for mutant bacterial cells by culturing them in a specific condition. In case of loss of function mutation, a master plate of mutagenized cells should be prepared. The cell from this master plate should be replica plated onto a culture plate requiring the wildtype gene function.
2. The selection strategy should test for the presence or absence of the wildtype gene function in the population of mutants. It should be clear from the beginning of the experiment about the functional consequences of the specific mutation in a cell. The study of Escherichia coli O157:H7 genes required for the growth and survival at pH (potential of hydrogen) 2.0 is done through the screening of mutant bacterial cells that are unable to grow at pH 2.
3. The mutant cells should possess a selectable marker like antibiotic resistance gene. This eases the differentiation between wildtype and mutant cells.
4. The identified mutant cells should be further selected using specific DNA (deoxyribonucleic acid) probes. In case of transposon mediated insertional mutation of target genes, a pair of primers is used to amplify the junction between the insertionally inactivated gene and transposon. The sequencing of the amplified product using transposon specific primer determines the insertion site and the gene into which the insertion has taken place.
Want to see more full solutions like this?
Chapter 12 Solutions
MICROBIOLOGY: EVOLV.SCI.-W/ACCESS>CI<
- , if one of the archaeological specimens lacked the celiac disease-causing epitope, how could PCR be used to identify the allele in a contemporary germplasm collection of wild wheats, and to assist in transferring the allele to modern wheat varieties?arrow_forwardNow you will consider the composition of lipoproteins, including where they are synthesized, how they circulate, and where the various lipid and protein components are located within the lipoprotein molecule. Drag the appropriate labels to their respective targets.arrow_forwardThe Oregon Wolfe Barley mapping population is unique in having 12 easily-scored morphological markers, each showing monogenic inheritance. Do you consider these markers useful? Briefly defend your answer, pointing out advantages and disadvantages of morphological vs. molecular markers.arrow_forward
- Biopharmaceutics and Pharmacokinetics:Two-Compartment Model Instant Absorption Questions Calculate these : a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forwardIn a population of Jackalopes (pictured below), horn length will vary between 0.5 and 2 feet, with the mean length somewhere around 1.05 feet. You pick Jackalopes that have horn lengths around 1.75 feet to breed as this appears to be the optimal length for battling other Jackalopes for food. After a round of breeding, you measure the offsprings' mean horn length is 1.67. What is the heritability of horns length (h2)? Is Jackalope horn length a heritable trait? (4 pts)? 12pt v R Paragraph V BIU A श्र > Barrow_forwardThere are many differences between DNA replication happening during mitosis in a Douglas fir tree growing in the Oregon Cascade Mountains and DNA replication happening during a PCR reaction in a forestry research lab at Oregon State University where the laboratory is amplifying a Simple Sequence Repeat. Complete the following table that compares the two DNA replication events in terms of the primers, the nucleotides, the polymerase, and the target sequence. Additionally, give a general value for the number of copies of the template DNA after one S phase in one cell and after the lab has completed the PCR reaction. Tree SSR Type your answer here: Primers Nucleotides Polymerase Target sequence Number of copiesarrow_forward
- Describe how insulin binding to its receptor induces glucose uptake in healthy individuals. Please specifyeach step in the cascade and use a diagram to illustrate the answer.arrow_forwardThere is a patient with breast cancer, after staining the breast tissue with H&E, state the molecular subtype of the tumour extracted. Results of H&E staining are down belowarrow_forwardBiopharmaceutics and Pharmacokinetics:Two-Compartment Model Instant Absorption Questions Calculate these : a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forward
- Use the Henderson-Hasselbalch equation for a propanoic acid solution (CH₂CH₂CO₂H, pK₁ = 4.874) to calculate the quotient [A-]/[HA] at three different pH values. pH = 4.479 [A-] [HA] [A-] pH = 4.874 [HA] = pH = 5.220 [A-] = [HA]arrow_forwardIn order to establish the expiration date of perishable food, growth curve data must be collected. Once the microbial load is so high that it poses a hazard to human health, the food item is no longer considered safe (expired). Generally a load of x50,000 bacteria/gram is considered unsafe. Your task is to determine the microbial growth curves for MicroYo, a new brand of yogurt. The growth is determined by sampling the yogurt and growing the bacterial isolates in broth culture which is then serially diluted by a total of x10,000 and inoculated onto standard petri plates of nutrient agar. The following colony counts are measured: Time (days) MicroYo colony count# 1 1 4 1 12 2 16 20 4 7 What day should you recommend expiring the yogurt (the last possible date before the microbial load is unsafe). 12 4 20 16arrow_forward9. Chicken combs in chickens is an example where you see interactions between genes. See potential genotypes and phenotypes below. Which genotype, when mated to a rose comb chicken, will produce progeny that are 50% walnut comb and 50% pea comb? walnut (RRPP) walnut (RrPP) pea (rrPP) walnut (RRPP) walnut (RrPp) pea (rrPp) rose rose single (RRPP) (Rrpp) (rrpp)arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningHuman Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
- Principles Of Radiographic Imaging: An Art And A ...Health & NutritionISBN:9781337711067Author:Richard R. Carlton, Arlene M. Adler, Vesna BalacPublisher:Cengage LearningCase Studies In Health Information ManagementBiologyISBN:9781337676908Author:SCHNERINGPublisher:CengageConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305251052/9781305251052_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305112100/9781305112100_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337711067/9781337711067_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781938168116/9781938168116_smallCoverImage.gif)