Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 12, Problem 1RE
Explanation of Solution
Steps in the process of object-oriented design:
Step 1: Gather program requirements.
The development starts by collecting the requirements and its documentation.
Step 2: Discover classes.
The second step is to find the appropriate classes for the program. To find the classes, the user need to search for the nouns in the problem description.
Step 3: Determine the responsibilities of each class and identify collaborating classes.
In this step, use CRC card to determine the responsibilities of each classes ad their collaborating classes to solve these responsibilities.
Step 4: Determine the relationships between the classes.
In the fourth step, the user need to identify the relationships (Inheritance, Interface Implementation, Aggregation and Dependency) between the classes.
Step 5: Document the behaviour of classes using Javadoc comments.
In this step, the behaviour of the classes are documented using the “javadoc” comments.
Step 6: Implement classes.
In the final step, the user should generate the code for implementing the classes.
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Please answer JAVA OOP problem below:
You are working at a university that tracks students. Each student is identified by their name and faculty advisor. Each faculty advisor is identified by their name, department, and maximum number of students they can advise.
Using solid OO design principles, create a modular program that implements all the classes for the problem and also creates an implementation class that gathers user input for one student and then prints out the information gathered by creating the appropriate data definition and implementation classes. All data must be validated.
I have given the code so far:
Implementation:
import javax.swing.JOptionPane;
public class Implementation {
public static void main(String[] args) {
FacultyAdvisor facultyAdvisor = new FacultyAdvisor("Sharmin Sultana", "IT", 30);
Student student = new Student("John", facultyAdvisor);
JOptionPane.showMessageDialog(null, student.toString());
}
}
Student:
public…
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head
{
NULL) return 0;B
= first;
while (head->next != NULL) {
if (head == first) {
return 1; }
head
head->next;
}
return 0;
void test_11_has_cycle() {
int i;
node nodes [6];
for (i = 0; i < 6; i++)
nodes [i] .next = NULL;
nodes [i].value
i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next = &nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next = & nodes [4];
nodes [4] .next
=
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
hass cycle\n\n", 11_has_cycle (&nodes [0]) ?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
checkpoint exercice for my students for Amortized Analysis
Chapter 12 Solutions
Big Java Late Objects
Ch. 12.1 - Prob. 1SCCh. 12.1 - Prob. 2SCCh. 12.1 - Prob. 3SCCh. 12.1 - Prob. 4SCCh. 12.1 - Prob. 5SCCh. 12.2 - Prob. 6SCCh. 12.2 - Prob. 7SCCh. 12.2 - Prob. 8SCCh. 12.2 - Prob. 9SCCh. 12.2 - Prob. 10SC
Ch. 12.2 - Prob. 11SCCh. 12.2 - Prob. 12SCCh. 12.3 - Prob. 13SCCh. 12.3 - Prob. 14SCCh. 12 - Prob. 1RECh. 12 - Prob. 2RECh. 12 - Prob. 3RECh. 12 - Prob. 4RECh. 12 - Prob. 5RECh. 12 - Prob. 6RECh. 12 - Prob. 7RECh. 12 - Prob. 8RECh. 12 - Prob. 9RECh. 12 - Prob. 10RECh. 12 - Prob. 11RECh. 12 - Prob. 12RECh. 12 - Prob. 13RECh. 12 - Prob. 14RECh. 12 - Prob. 15RECh. 12 - Prob. 1PECh. 12 - Prob. 2PECh. 12 - Prob. 3PECh. 12 - Prob. 4PECh. 12 - Prob. 5PECh. 12 - Prob. 6PECh. 12 - Prob. 1PPCh. 12 - Prob. 2PPCh. 12 - Prob. 3PPCh. 12 - Prob. 4PPCh. 12 - Prob. 5PPCh. 12 - Prob. 6PPCh. 12 - Prob. 7PPCh. 12 - Prob. 8PPCh. 12 - Prob. 9PPCh. 12 - Prob. 10PP
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