BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 12, Problem 1IP
How much force must be applied by a kicker to give a stationary 2.5-kg ball an acceleration of 40 m/s2? (Answer: 100 N)
Expert Solution & Answer
Summary Introduction
To determine: The force applied by a kicker on a stationary ball.
Answer to Problem 1IP
The force applied by a kicker on a stationary ball is
Explanation of Solution
Calculation:
Write an expression to find the force.
Here, m is the mass of the ball, a is the acceleration, and F is the force on ball.
Substitute 2.5 kg for m and
Conclusion
Therefore, the force applied by a kicker on a stationary ball is
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
When Galileo Galilei rolled a ball down an inclined plane, it traveled 1.0 meters in the first second, and a total of 4.0 meters in the first two seconds. What was its acceleration on this inclined plane?
2.0 meters per second2
3.0 meters per second2
4.0 meters per second2
5.0 meters per second2
6.0 meters per second2
Suppose as astronaut has landed on Mars. Fully equipped, the astronaut has a mass of 130 kg, and when the astronaut gets in scale, the reading is 477 N. What is the acceleration due to gravity on Mars?
A scientist was investigating if differences in the frictional work performed on a model car can change
depending on its mass (in grams) and whether the car moves up or down an inclined plane. They decided to
measure the amount of frictional force experienced by the model car and the distance it traveled in meters.
The scientists were able to evaluate the frictional work using the following data.
Mass (g)
Distance (m) Force
Work Done by Friction (J)
car going up the incline
100
39
0.063
2.457
car going down the incline 70
39
0.2309 ?
It is known that the relationship between force and distance determines the work done by friction (W+).
W₁ = fd
Wf work done by friction
f = force
d = distance
Question:
How much work done by friction was exerted on the car as it moved down the inclined plane?
You may use a calculator.
1
2.457
9.005
11.46
16.16
PREVIOUS
FINISH
Chapter 12 Solutions
BASIC BIOMECHANICS
Ch. 12 - How much force must be applied by a kicker to give...Ch. 12 - A high jumper with a body weight of 712 N exerts a...Ch. 12 - What factors affect the magnitude of friction?Ch. 12 - If s between a basketball shoe and a court is...Ch. 12 - A football player pushes a 670-N blocking sled....Ch. 12 - Lineman A has a mass of 100 kg and is traveling...Ch. 12 - Prob. 7IPCh. 12 - A ball dropped on a surface from a 2-m height...Ch. 12 - A set of 20 stairs, each of 20-cm height, is...Ch. 12 - A pitched ball with a mass of 1 kg reaches a...
Ch. 12 - Identify three practical examples of each of...Ch. 12 - Prob. 2APCh. 12 - A 2-kg block sitting on a horizontal surface is...Ch. 12 - Explain the interrelationships among mechanical...Ch. 12 - Prob. 5APCh. 12 - A 108 cm, 0.73-kg golf club is swung for 0.5 s...Ch. 12 - A 6.5-N ball is thrown with an initial velocity of...Ch. 12 - Prob. 8APCh. 12 - Using the principle of conservation of mechanical...Ch. 12 - Prob. 10AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, bioengineering and related others by exploring similar questions and additional content below.Similar questions
- Rotate the ball horizontally on an 80 cm long non-stretchable cord with angular velocity of 3 s^(-1). After ten seconds of clockwise rotation, the cord breaks. At what speed and in what direction does the ball fly, if it was faced north at time t = Os? Where and after how much time does the ball land on the ground that is 1 m below the plaine in which we rotate the string? {Solution: v= (0.37 m/s,2.37 m/s); d=1.07 m, t=0.447 s.) }arrow_forwardWhat was the ball’s acceleration on the inclined plane described above? 2.0 meters per second2 B. 3.0 meters per second2 4.0 meters per second2 6.0 meters per second2 8.0 meters per second2arrow_forwardAccording to Jean Buridan’s equation, the momentum or “impetus” of an 8 kilogram mass moving at 48 meters per second would be: 192 kilogram-meters per second 384 kilogram-meters per second 576 kilogram-meters per second 768 kilogram-meters per second 960 kilogram-meters per secondarrow_forward
- A spring has a constant of 875 N/m. What hanging-mass will cause this spring to stretch 4.5 m?arrow_forward72. Find J and K in the rotational system shown in Figure P4.18 to yield a 30% overshoot and a sett- ling time of 3 seconds for a step input in torque. [(Section: 4.6] 000 K FIGURE P4.18arrow_forwardWhat is the relationship between Net force, mass and acceleration. Newton’s second law of motion?arrow_forward
- Calculate the total amount of work performed in 5 minutes of exercise on the cycle ergometer, given the following:Resistance on the flywheel = 25 NCranking speed = 60 rpmDistance traveled per revolution = 6 metersarrow_forwardIn terms of mass and acceleration, what is the equation for force?arrow_forwardDefine the following parameters that can be assessed via isokinetic dynamometry (attempt to use your own words after reviewing data sheet): Peak Torque Time to peak torque Angle of peak torque Torque at 0.2 seconds Peak torque/body weight Total work Work fatigue (Fatigue Index) Average powerarrow_forward
- The “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardThe “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) C. (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forward15. A 2000-kg vehicle travelling 30 m/s takes 10 s to stop. What force did the venicie experience? Show your work. 16. If the time it takes to stop a car doubles, the force the vehicle experiences is Return to page 65 of the Student Module Booklet and begin Lessorarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles Of Radiographic Imaging: An Art And A ...Health & NutritionISBN:9781337711067Author:Richard R. Carlton, Arlene M. Adler, Vesna BalacPublisher:Cengage Learning
Principles Of Radiographic Imaging: An Art And A ...
Health & Nutrition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Cengage Learning
Chapter 7 - Human Movement Science; Author: Dr. Jeff Williams;https://www.youtube.com/watch?v=LlqElkn4PA4;License: Standard youtube license