Formula for given ionic compound rubidium iodide.

Question

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Answer 1

Question

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

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Answer 2

Question

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

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Answer 3

Question

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

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Answer 4

Question

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

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Answer 5

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

Answer 6

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

Answer 7

Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

Answer 8

(a)

Expert Solution

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge −1 . Therefore, Iodine has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I− , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

Answer 13

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

Answer 14

(b)

To determine

Formula for given ionic compound cesium phosphide.

Answer 15

(b)

Expert Solution

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge −3 . Phosphide has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3− , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

Answer 20

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

Answer 21

(c)

To determine

Formula for given ionic compound lithium sulfate.

Answer 22

(c)

Expert Solution

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42− , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42− .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

Answer 27

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

Answer 28

(d)

To determine

Formula for given ionic compound silver carbonate.

Answer 29

(d)

Expert Solution

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of −2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32− , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32− .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

Answer 34

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Answer 35

(e)

To determine

Formula for given ionic compound zinc phosphate.

Answer 36

(e)

Expert Solution

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of −3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43− , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43− .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Answer 41

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

Answer 42

(f)

To determine

Formula for given ionic compound aluminium nitrate.

Answer 43

(f)

Expert Solution

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of −1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31− , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31− .