Bundle: Welding: Principles and Applications, 8th + MindTap Welding, 4 terms (24 months) Printed Access Card
8th Edition
ISBN: 9781337219426
Author: Larry Jeffus
Publisher: Cengage Learning
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Textbook Question
Chapter 12, Problem 15R
What are the main limitations of the rutile fluxes?
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Problem 1. Rod OAB is rotating counterclockwise with the constant angular velocity of 5 rad/s.
In the position shown, collar P is sliding toward A with the constant speed of 0.8 m/s relative to
the rod. Find the velocity of P and the acceleration of P.
y
B
3
P
300 mm
A
-
Answer: Up = -0.861 − 0.48ĵ™; ā₂ = 4.8î −1.1ĵ
m
A bent tube is attached to a wall with brackets as shown. . A
force of F = 980 lb is applied to the end of the tube with
direction indicated by the dimensions in the figure.
a.) Determine the force vector F in Cartesian components.
→
→
b.) Resolve the force vector F into vector components
parallel and perpendicular to the position vector rDA.
Express each of these vectors in Cartesian components.
2013 Michael Swanbom
cc 10
BY NC SA
g
x
B
A
א
Z
FK
с
кая
b
Values for dimensions on the figure are given in the table
below. Note the figure may not be to scale. Be sure to align
your cartesian unit vectors with the coordinate axes shown in
the figure.
Variable
Value
a
8 in
12 in
с
15 in
36 in
h
23 in
g
28 in
a. F =
b. FDA =
= (
+
k) lb
k) lb
FIDA =
2 +
k) lb
Problem 4. Part 1
100 mm
C
@
PROBLEM 15.160
Pin P slides in the circular slot cut in the plate shown at a
constant relative speed u = 500 mm/s. Assuming that at the
instant shown the angular velocity of the plate is 6 rad/s and
is increasing at the rate of 20 rad/s², determine the
acceleration of pin P when = 90°.
150 mm
is NOT zero. Answer: a = 3.4î −15.1ĵ m/s² )
P
(Hint: u is a constant number, which means that the tangential component of F is zero.
However, the normal component of
Part2. When 0 = 120°, u = 600 mm/s and is increasing at the rate of 30mm/s², determine the
acceleration of pin P.
Chapter 12 Solutions
Bundle: Welding: Principles and Applications, 8th + MindTap Welding, 4 terms (24 months) Printed Access Card
Ch. 12 - List some factors that have led to the increased...Ch. 12 - How is FCAW similar to GMAW?Ch. 12 - What does the FCA flux provide to the weld?Ch. 12 - What are the major atmospheric contaminations of...Ch. 12 - How does slag help an FCA weld?Ch. 12 - How can FCA welding guns be cooled?Ch. 12 - Excessive drive roller pressure causes what...Ch. 12 - List the advantages that FCA welding offers the...Ch. 12 - Describe the two methods of manufacturing FCA...Ch. 12 - Why are the large diameter electrodes not used for...
Ch. 12 - How do deoxidizers remove oxygen from the weld...Ch. 12 - What do fluxing agents do for a weld?Ch. 12 - Why are alloying elements added to the flux?Ch. 12 - How does the flux form a shielding gas to protect...Ch. 12 - What are the main limitations of the rutile...Ch. 12 - Why is it more difficult to use lime-based fluxed...Ch. 12 - What benefit does adding an externally supplied...Ch. 12 - How do excessive amounts of manganese affect a...Ch. 12 - Why are elements added that cause ferrite to form...Ch. 12 - Why must a flux form a less dense slag?Ch. 12 - Referring to Table 12-5, what is the AWS...Ch. 12 - Describe the meaning of each part of the following...Ch. 12 - What does the number 316 in E316T-1 mean?Ch. 12 - What is the advantage of using an argon- CO2 mixed...Ch. 12 - Why are some slags called refractory?Ch. 12 - What can happen to slag that solidifies on the...Ch. 12 - How is the electrode extension measured?Ch. 12 - What can cause porosity in an FCA weld?Ch. 12 - What happens to water in the welding arc?Ch. 12 - What is the thin dark gray or black layer on new...Ch. 12 - Why is uniformly scattered porosity hard to detect...Ch. 12 - What cautions must be taken when chemically...
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- Problem 5. Disk D of the Geneva mechanism rotates with constant counterclockwise angular velocity wD = 10 rad/s. At the instant when & = 150º, determine (a) the angular velocity of disk S, and (b) the velocity of pin P relative to disk S. (c). the angular acceleration of S. Disk S R=50 mm =135° |1=√ER- Disk D Partial answers: Ō = -4.08 Â rad/s ā¸ = -233 k rad/s²arrow_forwardProblem 3. In the figure below, point A protrudes from link AB and slides in the rod OC. Rod OC is rotating with angular velocity woc = 2 rad/s and aoc = 3 rad/s² in the directions shown. Find the following, remembering to clearly define your axes and the rate of rotation of the frame. a. The angular velocity of link AB and the velocity of A relative to rod OC. m (Answers: @AB is 2.9 rad/s CCW, rxy = .58! toward C) S b. The angular acceleration of link AB and the acceleration of A relative to rod OC. Answers: αAB = 7.12 rad/s² CCW, r = 6.3 m ܐܨ toward C. B C A 30° Фос 400 mm OA=500 mm docarrow_forwardProblem 2. 6 m 30° B PROBLEM 15.164 At the instant shown the length of the boom AB is being decreased at the constant rate of 0.2 m/s and the boom is being lowered at the constant rate of 0.08 rad/s. Determine (a) the velocity of Point B, (b) the acceleration of Point B. Partial answer: a = −0.049î +0.009ĵ m/s²arrow_forward
- A crate is hung by three ropes attached to a steel ring at A such that the top surface is parallel to the xy plane. Point A is located at a height of h = 121.92 cm above the top of the crate directly over the geometric center of the top surface. Use the given dimensions from the table below to perform the following calculations: →> a.) Determine the position vector IAD that describes rope AD. b.) Compute the unit vector cд that points from point C to point A. c.) If rope AB carries a tension force of magnitude FT = 760 → N, determine the force vector FT that expresses how this force acts on point A. Express each vector in Cartesian components to three significant figures. 2013 Michael Swanbom ↑z BY NC SA b x B У a D Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 101.6 cm b 124.46 cm с 38.71 cm a. rдD = + b. ÛCA c. FT= =…arrow_forwardF3 N< Ꮎ 2 F2 -Y F1 There are 3 forces acting on the eye bolt. Force F1 acts on the XY plane has a magnitude of 536 lbf, and the angle of 0 = 38°. Force F2 acts on the YZ plane has a magnitude of 651 lbf, and the angle = 41°. Force F3 has a magnitude of 256 lb, and coordinate. = f direction angles of a 71°, B = 115°, and y = 33°. Determine the resultant force on the eye bolt. FR = ( + k) lbf FR magnitude: FR coordinate direction angle a: deg FR coordinate direction angle ẞ`: deg FR coordinate direction angle y: deg lbfarrow_forwardBall joints connect the ends of each of the struts as shown. The resulting structure supports a force of F = 1925 N which lies in the xz plane. a.) Determine the angle (in degrees) between strut AD and strut AC. b.) Determine the dimension g such that the force Fis →> perpendicular to гAC. 2013 Michael Swanbom CC BY NC SA B b C h/ L 不 g F ୮ d y LLC Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 4.8 cm b 13.4 cm C 11.6 cm d 10.4 cm h 4.4 cm k 14.8 cm a. The angle between strut AD and strut AC is b. The dimension g is deg. cm.arrow_forward
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