
Concept explainers
The trip distribution using the average growth factor method.

Answer to Problem 14P
The trip distribution has been developed using the average growth factor method.
Explanation of Solution
Given:
For Zone
Present total observed trip ends is
Zonal growth rate is
For Zone
Present total observed trip ends is
Zonal growth rate is
For Zone
Present total observed trip ends is
Zonal growth rate is
For Zone
Present total observed trip ends is
Zonal growth rate is
Formula used:
Estimated growth total is given by,
The number of trips estimated from zone
Here,
The new growth factor is given as,
Calculation:
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The data of
Zones | |||
Table (1)
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The calculated trips from zone
Zones | |
Table (2)
The
The
Substitute
The
The
Substitute
The
The
Substitute
The
The
Substitute
The remaining movement between zones, new present total and new growth factor for zone s
Zones | New Present total | New Growth factor |
Table (3)
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The estimated growth total for zone
Substitute
The data of
Zones | |||
Table (4)
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The number of trips estimated from zone
Substitute
The calculated trips from zone
Zones | |
Table (5)
The
The
Substitute
The
The
Substitute
The
The
Substitute
The
The
Substitute
The remaining movement between zones, new present total and new growth factor for zone
Zones | New Present total | New Growth factor |
| ||
Table (6)
Conclusion:
The trip distribution has been done using the average growth factor method.
Want to see more full solutions like this?
Chapter 12 Solutions
Traffic and Highway Engineering
- Determine the following for the beam with unknown loading, using the Shear and Bending Diagrams provided in the figures on the right: a. The maximum shear stress experienced by the beam. b. The maximum flexural stress experienced by the beam (Indicate if this is tensile or compressive flexural stress) c. The loading diagram (Indicate the magnitudes of the loading/s. The loads are acting along the plane of symmetry of the section) 20 80 20 十十 SHEAR DIAGRAM x=577.3502692 mm 20 KN 1° 5/3 KN 2° C 2° D A B CROSS SECTION Dimensions are in mm LOADING DIAGRAM ? 120 40 40 A B C D 1000mm 2000mm 1000mm -55/3 KN MB' C D BENDING DIAGRAM MB A B Σ Mcarrow_forwardFind the maximum bending stress in ksi for this beam if it is made from a W16x50 steel shape. If the steel yields at 50 ksi, will the beam support the loads shown without permanently deforming? Confirm the max moment in the beam by drawing the shear and moment diagram. 18 kip-ft 2 kip/ft 9 ftarrow_forwardProblem 4 A propped cantilever beam of flexural rigidity EI and 2EI for parts 1-2 and 2-3, respectively, is subjected to a concentrated load P at point 2. Find: a) Determine the displacement at point 2; b) Determine the rotation at point 3; c) Determine the reaction force and moment at point 1; d) Determine the reaction force at point 3. El 2 P 2 EI 2 Larrow_forward
- Problem 3 15 A W150 x 37 rolled-steel beam is used below. Let P150 kN, L-10 m and E 200 GPa. Find the deflection and slope at each node and each pin or wall reaction. If a software program such Maple or MATLAB issued as part of the solution, a hard copy of the code must be submitted too. 1/2 1/2arrow_forward1. Determine the bearings, azimuths, and lengths of lines AB, BC, CD, and DA for the closed loop traverse data shown below in Table 1. Show calculations. Table 1 Station Northing [ft] Easting [ft] A 1,000 1,000 B 750 1,750 C 1,345 2,255 D 1,567 1,345 2. Compute the bearings of sides BC and CD in Figure 1. Show all work for all angles. A B 70°10' S72°39'W C 94°35' Figure 1 Tt (+) B Darrow_forwardhoph - AT 10x AT 10.076 ht 0.076 0 0-1846112 14884 xh T 1.632m h-4- (1-22) h = 1.022m 14. The 4-ft-diameter cylinder, 4 ft long, is acted upon by water on the left and oil of sp gr 0.800 on the right. Determine (a) the normal force at B if the cylinder weighs 4000 lb and (b) the horizontal force due to oil and water if the oil level drops 1 ft. Solution Water Oil Barrow_forward
- 3. The following data was collected for the traverse shown in Figure 2. a. Determine the latitudes and departures for all sides. b. Determine the linear error of closure and the accuracy ratio. C. Correct and balance the latitudes and departures. A N80°27'E 467.81 ft 497.50 ft N56°46' W B S34°51'E 483.69 ft 325.06 ft D N81°48' Warrow_forwardPlease answer the questions in the picture. Thank you for your help!arrow_forward1500 N A B 3500 N/m 1.2 m 3.6 m 1.2 m 1800 N Beam Cross-section: 4b T D b 25 mm 100 mm For beam ABCD with cross-section shown, design the beam by determining the following: Draw the shear and bending moment diagrams (show your detailed computations to get credit) The minimum dimension for b [mm], knowing that the allowable flexural stress and transverse shear stress are 10 MPa and 0.5 MPa, respectively.arrow_forward
- Civil engineering quantiarrow_forwardPlease answer the questions in the picture. Thank you for your help. For part B use the Second Picture.arrow_forwardDerive by deconvolution the six-hour unit hydrograph from the following data for a watershed having a drainage area of 216 km2 , assuming a constant rainfall abstraction rate and a constant baseflow of 20 m3 /s. Six-hour period 1 2 3 4 5 6 7 8 9 10 11 Rainfall (cm) 1.5 3.5 2.5 1.5 Streamflow (m3 /s) 26 71 174 226 173 99 49 33 26 22 21 Use the unit hydrograph developed to calculate the streamflow hydrographfrom a 12 hour-duration storm having 2 cm of rainfall excess in the first six hours and 3 cm inthe second six hours. Assume a constant baseflow rate of 30 m3/s.arrow_forward
- Traffic and Highway EngineeringCivil EngineeringISBN:9781305156241Author:Garber, Nicholas J.Publisher:Cengage LearningEngineering Fundamentals: An Introduction to Engi...Civil EngineeringISBN:9781305084766Author:Saeed MoaveniPublisher:Cengage LearningFundamentals Of Construction EstimatingCivil EngineeringISBN:9781337399395Author:Pratt, David J.Publisher:Cengage,
- Residential Construction Academy: House Wiring (M...Civil EngineeringISBN:9781285852225Author:Gregory W FletcherPublisher:Cengage Learning



