Elementary Statistics 2nd Edition
2nd Edition
ISBN: 9781259724275
Author: William Navidi, Barry Monk
Publisher: McGraw-Hill Education
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Chapter 12, Problem 12CQ
To determine
To find: To find the test statistics.
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
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Chapter 12 Solutions
Elementary Statistics 2nd Edition
Ch. 12.1 - In Exercises 9 and 10, fill in each blank with the...Ch. 12.1 - Prob. 10ECh. 12.1 - In Exercises 11 and 12, determine whether the...Ch. 12.1 - Prob. 12ECh. 12.1 - Find the =0.05 critical value for the chi-square...Ch. 12.1 - Find the =0.01 critical value for the chi-square...Ch. 12.1 - Find the area to the right of 24.725 under the...Ch. 12.1 - Find the area to the right of 40.256 under the...Ch. 12.1 - For the following observed and expected...Ch. 12.1 - For the following observed and expected...
Ch. 12.1 - Following are observed frequencies. The null...Ch. 12.1 - Following are observed frequencies. The null...Ch. 12.1 - Is the lottery fair? Mega Millions is a multistate...Ch. 12.1 - Grade distribution: A statistics teacher claims...Ch. 12.1 - False alarm: The numbers of false fire alarms were...Ch. 12.1 - Crime rates: The FBI computed the proportion of...Ch. 12.1 - Prob. 25ECh. 12.1 - Prob. 26ECh. 12.1 - Economic future: A Heartland Monitor poll taken in...Ch. 12.1 - Prob. 28ECh. 12.1 - Fair die? A gambler rolls a die 600 times to...Ch. 12.2 - In Exercises 3-5, fill in each blank with the...Ch. 12.2 - Prob. 4ECh. 12.2 - Prob. 5ECh. 12.2 - Prob. 6ECh. 12.2 - Prob. 7ECh. 12.2 - In Exercises 6-8, determine whether the statement...Ch. 12.2 - For the given table of observed frequencies:...Ch. 12.2 - For the given table of observed frequencies:...Ch. 12.2 - Carbon monoxide: A recent study examined the...Ch. 12.2 - Beryllium disease: Beryllium is an extremely...Ch. 12.2 - No smoking: The General Social Survey conducted a...Ch. 12.2 - How big is your family? The General Social Survey...Ch. 12.2 - Age discrimination: The following table presents...Ch. 12.2 - Schools and museums: Do people who are interested...Ch. 12.2 - Prob. 17ECh. 12.2 - Prob. 18ECh. 12.2 - Prob. 19ECh. 12.2 - Are you an optimist? The General Social Survey...Ch. 12 - A contingency table containing observed values has...Ch. 12 - Prob. 2CQCh. 12 - Prob. 3CQCh. 12 - Prob. 4CQCh. 12 - Prob. 5CQCh. 12 - Prob. 6CQCh. 12 - Exercises 4-9 refer to the following data:...Ch. 12 - Prob. 8CQCh. 12 - Exercises refer to the following data: Electric...Ch. 12 - Prob. 10CQCh. 12 - Exercises 10-15 refer to the following data:...Ch. 12 - Prob. 12CQCh. 12 - Prob. 13CQCh. 12 - Prob. 14CQCh. 12 - Prob. 15CQCh. 12 - Prob. 1RECh. 12 - Prob. 2RECh. 12 - Prob. 3RECh. 12 - Prob. 4RECh. 12 - Prob. 5RECh. 12 - Prob. 6RECh. 12 - Prob. 7RECh. 12 - Prob. 8RECh. 12 - Prob. 9RECh. 12 - Prob. 10RECh. 12 - Prob. 11RECh. 12 - Prob. 12RECh. 12 - Prob. 13RECh. 12 - Prob. 14RECh. 12 - Prob. 15RECh. 12 - Prob. 1WAICh. 12 - Prob. 2WAICh. 12 - Prob. 3WAICh. 12 - Prob. 4WAICh. 12 - Prob. 1CSCh. 12 - Prob. 2CSCh. 12 - Prob. 3CSCh. 12 - Prob. 4CSCh. 12 - Prob. 5CSCh. 12 - Prob. 6CSCh. 12 - Prob. 7CSCh. 12 - We conclude that department is associated with...
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- You want to compare the average number of tines on the antlers of male deer in two nearby metro parks. A sample of 30 deer from the first park shows an average of 5 tines with a population standard deviation of 3. A sample of 35 deer from the second park shows an average of 6 tines with a population standard deviation of 3.2. Find a 95 percent confidence interval for the difference in average number of tines for all male deer in the two metro parks (second park minus first park).Do the parks’ deer populations differ in average size of deer antlers?arrow_forwardSuppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forwardA random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forward
- Suppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forwardIs it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forwardTines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forward
- Based on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forwardA 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forward
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