(a) Interpretation: The beaker with the resultant product should be identified. Concept introduction: The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

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Answer 1

Question

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

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2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled** Peak Chemical Shift (d) 5.7 1 Multiplicity multiplate .......... 5.04 double of doublet 2 4.98 double of doublet 3 4.05 doublet of quartet 4 5 LO 3.80 quartet 1.3 doublet 6 Peak Chemical Shift (d) Multiplicity

Interpreting NMR spectra is a skill that often requires some amount of practice, which, in turn, necessitates access to a collection of NMR spectra. Beyond Labz Organic Synthesis and Organic Qualitative Analysis have spectral libraries containing over 700 1H NMR spectra. In this assignment, you will take advantage of this by first predicting the NMR spectra for two closely related compounds and then checking your predictions by looking up the actual spectra in the spectra library. After completing this assignment, you may wish to select other compounds for additional practice. 1. Write the IUPAC names for the following two structures: Question 2 Question 3 2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled**

11:14 ... worksheets.beyondlabz.com 3. To check your predictions, click this link for Interpreting NMR Spectra 1. You will see a list of all the - compounds in the spectra library in alphabetical order by IUPAC name. Hovering over a name in the list will show the structure on the chalkboard. The four buttons on the top of the Spectra tab in the tray are used to select the different spectroscopic techniques for the selected compound. Make sure the NMR button has been selected. 4. Scroll through the list of names to find the names for the two compounds you have been given and click on the name to display the NMR spectrum for each. In the NMR tables below, list the chemical shift, the splitting, and the number of hydrogens associated with each peak for each compound. Compare your answers to your predictions. **Not all slots must be filled** Peak Chemical Shift (d) Multiplicity 1 2 3 4 5

Answer 2

Question

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Expert Solution & Answer

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Answer 3

Question

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Expert Solution & Answer

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Answer 4

Question

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Expert Solution & Answer

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See solution

Answer 5

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 6

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 7

Chapter 12, Problem 12.91UTC

Interpretation Introduction

(a)

Interpretation:

The beaker with the resultant product should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Ionic equation should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 10

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 11

Interpretation Introduction

(c)

Interpretation:

Net reaction should be identified.

Concept introduction:

The sodium ion linked with the chloride ions in beaker 1 whereas silver ions are present with nitrate and on mixing both the solution the ionic compound will remain as ion in the solution whereas the non ionic will precipitate down.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 12.1 - Prob. 12.1QAP Ch. 12.1 - Prob. 12.2QAP Ch. 12.1 - Prob. 12.3QAP Ch. 12.1 - Prob. 12.4QAP Ch. 12.1 - Prob. 12.5QAP Ch. 12.1 - Water is a polar solvent and hexane is a nonpolar...Ch. 12.2 - Prob. 12.7QAP Ch. 12.2 - Prob. 12.8QAP Ch. 12.2 - Write a balanced equation for the dissociation of...Ch. 12.2 - Prob. 12.10QAP

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Chapter 12 Solutions