Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 12, Problem 12.8CE12
Explanation of Solution
Compare and contrast answers to questions 12.6 and 12.7:
Refer to the textbook for question 12.6 and 12.7.
Here, option A represents an email based process to receive emails and rent properties to customers.
Option B represents a Shared
Option A:
Option A is relatively simple to create as compared to option B. Most of the importance will be given to accomplishing the goals of the alliance by agreeing on the business processes that will be used to facilitate the inter enterprise communication...
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 12 Solutions
Using MIS (9th Edition)
Ch. 12.4 - Prob. 1EGDQCh. 12.4 - Prob. 2EGDQCh. 12.4 - Prob. 3EGDQCh. 12.4 - Prob. 4EGDQCh. 12.4 - Prob. 6EGDQCh. 12.4 - Prob. 7EGDQCh. 12.4 - Prob. 8EGDQCh. 12.4 - Prob. 9EGDQCh. 12.4 - Prob. 10EGDQCh. 12.6 - Prob. 1KYNP
Ch. 12.6 - Prob. 2KYNPCh. 12.6 - Prob. 3KYNPCh. 12.6 - Prob. 4KYNPCh. 12.6 - Prob. 6KYNPCh. 12.7 - Prob. 1SGDQCh. 12.7 - Prob. 2SGDQCh. 12.7 - Prob. 3SGDQCh. 12.7 - Prob. 4SGDQCh. 12.7 - Prob. 5SGDQCh. 12.7 - Prob. 6SGDQCh. 12.7 - Prob. 7SGDQCh. 12.7 - Prob. 1FFWCh. 12.7 - Prob. 2FFWCh. 12.7 - Prob. 3FFWCh. 12.7 - Prob. 4FFWCh. 12.7 - Prob. 12.1ARQCh. 12.7 - Prob. 12.2ARQCh. 12.7 - Prob. 12.3ARQCh. 12.7 - Prob. 12.4ARQCh. 12.7 - Prob. 12.5ARQCh. 12.7 - Prob. 12.6ARQCh. 12.7 - Prob. 12.7ARQCh. 12 - Prob. 12.1UYKCh. 12 - Prob. 12.4UYKCh. 12 - Prob. 12.5UYKCh. 12 - Prob. 12.6CE12Ch. 12 - Prob. 12.7CE12Ch. 12 - Prob. 12.8CE12Ch. 12 - Prob. 12.9CE12Ch. 12 - Prob. 12.1CS12Ch. 12 - Prob. 12.11CS12Ch. 12 - Prob. 12.12CS12Ch. 12 - Prob. 12.13CS12Ch. 12 - Prob. 12.14CS12
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