Chapter 12, Problem 12.60QP

Interpretation Introduction

Interpretation:

Freezing point of solution made by condensation of $4L$ gas, at ${27}^{\circ }Cand748mmHg$ into $58g$ of benzene has to be calculated.

Concept introduction

Freezing point is the temperature at which liquid turns into solid.

Freezing point depression $\left({\text{ΔT}}_{\text{f}}\right)$ is indicated as follows,

${\text{ΔT}}_{\text{f}}{\text{= K}}_{\text{f}}\text{m}$

Where,

${\text{ΔT}}_{\text{f}}\text{-}$ Change in freezing point

${\text{K}}_{\text{f}}\text{-}$ Molal freezing point constant

$\text{m-}$ Molality of the solution

Ideal gas Equation: Any gas is described by using four terms namely pressure, volume, temperature and amount of gas. Thus combining three laws namely Boyle’s, Charles’s Law and Avogadro’s Hypothesis the following equation could be obtained. It is referred as ideal gas equation.

$\begin{array}{c}\text{V}\propto \frac{\text{nT}}{\text{P}}\\ \text{V=R}\frac{\text{nT}}{\text{P}}\\ \text{PV=nRT}\end{array}$

Where,

$\begin{array}{c}\text{n = moles of gas}\\ \text{P = pressure}\\ \text{T = temperature}\\ \text{R = gas constant}\end{array}$