To determine To calculate: The resultant internal loadings acting on the cross section through point B of the signpost. Explanation Given information: The post is fixed to the ground and a uniform pressure of 7 lb / ft 2 acts perpendicular to the face of the sign. Calculation: Sketch the Free Body Diagram of the sign post as shown in Figure 1. Refer to Figure 1. Find the internal loadings as shown below. Summation of forces along x direction is Equal to zero. ∑ F x = 0 ( V B ) x − 105 = 0 ( V B ) x = 105 lb Summation of forces along y direction is Equal to zero. ∑ F y = 0 ( V B ) y = 0 Summation of forces along z direction is Equal to zero. ∑ F z = 0 ( N B ) z = 0 Take moment about B at x direction is Equal to zero. ∑ M x = 0 ( M B ) x = 0 Take moment about B at y direction is Equal to zero. ∑ M y = 0 ( M B ) y − 105 × 7

9th Edition

ISBN: 9789810694364

Author: Russell C Hibbeler

Publisher: Pearson Education

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Types of loading

In mechanical terminology, the term load indicates that external force/weight, either constant or variable, acts on a mechanical member/structure. The weight of an object of a specific material is also an external load, and the external force that works …

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Chapter 1.2, Problem 1.25P

To determine

To calculate: The resultant internal loadings acting on the cross section through point B of the signpost.

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Chapter 1.2, Problem 1.24P

Chapter 1.2, Problem 1.26P

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Chapter 1 Solutions

Mechanics Of Materials, Si Edition

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