Explanation Given information: The reactions at the supports A and B are vertical. Calculation: Sketch the Free Body Diagram of the beam as shown in Figure 1. Refer to Figure 1. Find the loading intensity as shown below. P A D = P B D = 1 2 × Intensity of loading × Length of loading Substitute 6 kip / ft for intensity of loading and 6 ft for length of loading. P A D = P B D = 1 2 × 6 × 6 = 18 kip Find the support reactions as shown below. Apply the Equations of Equilibrium as shown below. Take moment about B is Equal to zero. ∑ M A = 0 ( 18 × 2 ) + ( 18 × 10 ) − ( A y × 12 ) = 0 216 − 12 A y = 0 − 12 A y = − 216 A y = 18 kip Summation of forces along vertical direction is Equal to zero. ∑ F y = 0 18 − 18 − 18 + B y = 0 − 18 + B y = 0 B y = 18 kip Sketch the Free Body Diagram of the beam segment AD as shown in Figure 2

9th Edition

ISBN: 9789810694364

Author: Russell C Hibbeler

Publisher: Pearson Education

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Types of loading

In mechanical terminology, the term load indicates that external force/weight, either constant or variable, acts on a mechanical member/structure. The weight of an object of a specific material is also an external load, and the external force that works …

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Chapter 1.2, Problem 1.20P

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To calculate: The resultant internal loadings acting on the cross section through point D.

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Chapter 1.2, Problem 1.19P

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Mechanics Of Materials, Si Edition

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The resultant internal loadings acting on the cross section through point D .

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