To determine To calculate: The resultant internal loadings acting on the cross section of the bone of the forearm at E . Explanation Given information: The biceps pulls on the bone along BD . Calculation: Sketch the Free Body Diagram of the forearm as shown in Figure 1. Refer to Figure 1. Find the support reactions as shown below. Take moment about C is Equal to zero. ∑ M C = 0 ( F B D sin 75 ° × 0.07 ) − ( 2 × 9.81 × 0.3 ) = 0 0.0676 F B D − 5.886 = 0 F B D = 87.07 N Summation of forces along horizontal direction is Equal to zero. ∑ F x = 0 C x − 87.07 cos 75 ° = 0 C x − 22.54 = 0 C x = 22.54 N Summation of forces along vertical direction is Equal to zero. ∑ F y = 0 87.07 sin 75 ° − 2 × 9.81 − C y = 0 64.48 − C y = 0 C y = 64.48 N Sketch the Free Body Diagram of section CE of the forearm as shown in Figure 2.

9th Edition

ISBN: 9789810694364

Author: Russell C Hibbeler

Publisher: Pearson Education

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Types of loading

In mechanical terminology, the term load indicates that external force/weight, either constant or variable, acts on a mechanical member/structure. The weight of an object of a specific material is also an external load, and the external force that works …

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Chapter 1.2, Problem 1.11P

To determine

To calculate: The resultant internal loadings acting on the cross section of the bone of the forearm at E.

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Chapter 1.2, Problem 1.10P

Chapter 1.2, Problem 1.12P

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Mechanics Of Materials, Si Edition

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