Chapter 12, Problem 12.58P

Interpretation Introduction

Interpretation:

The mass of ${\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{4}}\right)}_{\text{3}}{\text{·18 H}}_{\text{2}}\text{O}$ required to prepare $\text{500 mL}$ of $3{\text{ M Al}}_2{\left({\text{SO}}_4\right)}_3$ has to be explained.

Concept Introduction:

The formula to evaluate moles from molarity is given as follows:

  $n=MV$

Here,

$M$ denotes molarity.

$n$ denotes number of moles.

$V$ denotes volume.

The formula to convert mass in gram to moles is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{Molar mass}\right)$