Chemistry (7th Edition)
7th Edition
ISBN: 9780321943170
Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 12, Problem 12.42SP
Interpretation Introduction
Interpretation:
The larger (more negative)hydration energy should be selected from the followings:
(a) Na+ or Cs+
(b) K+ or Ba2+
Concept introduction:
The amount of heat released when new bonds are formed between the ions and the water molecules is called the hydration energy.
One of the factors that govern the hydration energy is the size of the ion.
Smaller ions have stronger attractions and so the hydration energies is higher. With increase in the size of the ion the hydration energy decreases.
As the charge on ion increases, the attractions also increase. And also hydration energy is also higher.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Write the complete common (not IUPAC) name of each molecule below.
Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is.
molecule
Ο
C=O
common name
(not the IUPAC
name)
H
☐
H3N
CH₂OH
0-
C=O
H
NH3
CH₂SH
H3N
☐
☐
X
G
(Part A) Provide structures of the FGI products and missing reagents (dashed box)
1 eq Na* H*
H
-H
B1
B4
R1
H2 (gas)
Lindlar's
catalyst
A1
Br2
MeOH
H2 (gas)
Lindlar's
catalyst
MeO.
OMe
C6H1402
B2
B3
A1
Product carbons' origins
Draw a box around product
C's that came from A1.
Draw a dashed box around
product C's that came from B1.
Classify each of the amino acids below.
Note for advanced students: none of these amino acids are found in normal proteins.
X
CH2
H3N-CH-COOH3N-CH-COO-
H3N-CH-COO
CH2
CH3-C-CH3
CH2
NH3
N
NH
(Choose one) ▼
(Choose one)
S
CH2
OH
(Choose one) ▼
+
H3N-CH-COO¯
CH2
H3N CH COO H3N-CH-COO
CH2
오오
CH
CH3
CH2
+
O
C
CH3
O=
O_
(Choose one)
(Choose one) ▼
(Choose one)
G
Chapter 12 Solutions
Chemistry (7th Edition)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2ACh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4ACh. 12 - PRACTICE 12.5 A 50.0 mL sample of drinking water...Ch. 12 - APPLY 12.6 The legal limit for human exposure to...Ch. 12 - PRACTICE 12.7 What mass in grams of a 0.500 m...Ch. 12 - APPLY 12.8 What is the molality of a solution...Ch. 12 - PRACTICE 12.9 The density at 20°C of a 0.500 M...Ch. 12 - APPLY 12.10 The density at 20°C of a 0.258 m...
Ch. 12 - Prob. 12.11PCh. 12 - APPLY 12.12 Use the Henry’s law constant you...Ch. 12 - PRACTICE 12.13 What is the vapor pressure in mm Hg...Ch. 12 - APPLY 12.14 A solution made by dissolving 8.110 g...Ch. 12 - Prob. 12.15PCh. 12 - Conceptual APPLY 12.16 The following diagram shows...Ch. 12 - PRACTICE 12.17 What is the vapor pressure of the...Ch. 12 - Conceptual APPLY 12.18 The following diagram shows...Ch. 12 - Prob. 12.19PCh. 12 - APPLY 12.20 The following phase diagram shows a...Ch. 12 - Prob. 12.21PCh. 12 - APPLY 12.22 Cells in the human eye have an osmotic...Ch. 12 - PRACTICE 12.23 A solution prepared by dissolving...Ch. 12 - Prob. 12.24ACh. 12 - PROBLEM 12.25 What is the difference between a...Ch. 12 - PROBLEM 12.26 Urea has a high solubility in blood...Ch. 12 - Prob. 12.27PCh. 12 - Prob. 12.28PCh. 12 - Many people take vitamin supplements to promote...Ch. 12 - Prob. 12.30CPCh. 12 - Prob. 12.31CPCh. 12 - Prob. 12.32CPCh. 12 - Prob. 12.33CPCh. 12 - Prob. 12.34CPCh. 12 - Prob. 12.35CPCh. 12 - Prob. 12.36CPCh. 12 - Prob. 12.37CPCh. 12 - Prob. 12.38CPCh. 12 - Prob. 12.39CPCh. 12 - Prob. 12.40SPCh. 12 - 12.41 Why do ionic substances with higher lattice...Ch. 12 - Prob. 12.42SPCh. 12 - Prob. 12.43SPCh. 12 - Classify the strongest type of intermolecular...Ch. 12 - Classify the strongest type of intermolecular...Ch. 12 - Prob. 12.46SPCh. 12 - Prob. 12.47SPCh. 12 - Prob. 12.48SPCh. 12 - Prob. 12.49SPCh. 12 - Prob. 12.50SPCh. 12 - Prob. 12.51SPCh. 12 - Prob. 12.52SPCh. 12 - Prob. 12.53SPCh. 12 - Prob. 12.54SPCh. 12 - Pentyl alcohol (Problem 12.54) is miscible with...Ch. 12 - Prob. 12.56SPCh. 12 - 12.57 The dissolution of NH4ClO4(s) in water is...Ch. 12 - Prob. 12.58SPCh. 12 - Prob. 12.59SPCh. 12 - Prob. 12.60SPCh. 12 - Prob. 12.61SPCh. 12 - Prob. 12.62SPCh. 12 - Prob. 12.63SPCh. 12 - Prob. 12.64SPCh. 12 - Prob. 12.65SPCh. 12 - Prob. 12.66SPCh. 12 - Prob. 12.67SPCh. 12 - Prob. 12.68SPCh. 12 - Prob. 12.69SPCh. 12 - Prob. 12.70SPCh. 12 - Prob. 12.71SPCh. 12 - Prob. 12.72SPCh. 12 - Prob. 12.73SPCh. 12 - Prob. 12.74SPCh. 12 - Prob. 12.75SPCh. 12 - Ethylene glycol, C2H6O2, is the principal...Ch. 12 - Ethylene glycol, C2H6O2, is a colorless liquid...Ch. 12 - Prob. 12.78SPCh. 12 - Prob. 12.79SPCh. 12 - Prob. 12.80SPCh. 12 - Prob. 12.81SPCh. 12 - Prob. 12.82SPCh. 12 - Prob. 12.83SPCh. 12 - Prob. 12.84SPCh. 12 - Hydrogen sulfide, H2S, is a toxic gas responsible...Ch. 12 - Prob. 12.86SPCh. 12 - Prob. 12.87SPCh. 12 - Prob. 12.88SPCh. 12 - Prob. 12.89SPCh. 12 - Prob. 12.90SPCh. 12 - Prob. 12.91SPCh. 12 - Prob. 12.92SPCh. 12 - Prob. 12.93SPCh. 12 - Prob. 12.94SPCh. 12 - Prob. 12.95SPCh. 12 - Prob. 12.96SPCh. 12 - Prob. 12.97SPCh. 12 - Prob. 12.98SPCh. 12 - Prob. 12.99SPCh. 12 - Prob. 12.100SPCh. 12 - Prob. 12.101SPCh. 12 - Prob. 12.102SPCh. 12 - Prob. 12.103SPCh. 12 - Prob. 12.104SPCh. 12 - Prob. 12.105SPCh. 12 - Prob. 12.106SPCh. 12 - Prob. 12.107SPCh. 12 - Prob. 12.108SPCh. 12 - Prob. 12.109SPCh. 12 - Prob. 12.110SPCh. 12 - Prob. 12.111SPCh. 12 - Prob. 12.112SPCh. 12 - Prob. 12.113SPCh. 12 - Prob. 12.114SPCh. 12 - Prob. 12.115SPCh. 12 - Prob. 12.116SPCh. 12 - Prob. 12.117SPCh. 12 - Prob. 12.118SPCh. 12 - Prob. 12.119SPCh. 12 - Prob. 12.120SPCh. 12 - Prob. 12.121SPCh. 12 - Prob. 12.122SPCh. 12 - Prob. 12.123SPCh. 12 - Prob. 12.124SPCh. 12 - Prob. 12.125SPCh. 12 - Prob. 12.126SPCh. 12 - Prob. 12.127SPCh. 12 - Prob. 12.128SPCh. 12 - Prob. 12.129SPCh. 12 - Prob. 12.130CPCh. 12 - Prob. 12.131CPCh. 12 - Prob. 12.132CPCh. 12 - Prob. 12.133CPCh. 12 - Prob. 12.134CPCh. 12 - Prob. 12.135CPCh. 12 - Prob. 12.136CPCh. 12 - Prob. 12.137CPCh. 12 - Prob. 12.138CPCh. 12 - There’s actually much more in seawater than just...Ch. 12 - Prob. 12.140CPCh. 12 - Prob. 12.141CPCh. 12 - Prob. 12.142CPCh. 12 - Prob. 12.143CPCh. 12 - Prob. 12.144CPCh. 12 - What is the value of the van’t Hoff factor for KCI...Ch. 12 - Prob. 12.146CPCh. 12 - Prob. 12.147CPCh. 12 - Prob. 12.148CPCh. 12 - Prob. 12.149CPCh. 12 - Prob. 12.150CPCh. 12 - Prob. 12.151CPCh. 12 - An aqueous solution of a certain organic compound...Ch. 12 - Prob. 12.153CPCh. 12 - Prob. 12.154CPCh. 12 - Prob. 12.155CPCh. 12 - Prob. 12.156CPCh. 12 - Prob. 12.157CPCh. 12 - Prob. 12.158CPCh. 12 - Prob. 12.159CPCh. 12 - Prob. 12.160MPCh. 12 - Prob. 12.161MPCh. 12 - Prob. 12.162MPCh. 12 - Prob. 12.163MPCh. 12 - Prob. 12.164MP
Knowledge Booster
Similar questions
- Another standard reference electrode is the standard calomel electrode: Hg2Cl2(s) (calomel) + 2e2 Hg() +2 Cl(aq) This electrode is usually constructed with saturated KCI to keep the Cl- concentration constant (similar to what we discussed with the Ag-AgCl electrode). Under these conditions the potential of this half-cell is 0.241 V. A measurement was taken by dipping a Cu wire and a saturated calomel electrode into a CuSO4 solution: saturated calomel electrode potentiometer copper wire CuSO4 a) Write the half reaction for the Cu electrode. b) Write the Nernst equation for the Cu electrode, which will include [Cu2+] c) If the voltage on the potentiometer reads 0.068 V, solve for [Cu²+].arrow_forward2. (Part B). Identify a sequence of FGI that prepares the Synthesis Target 2,4-dimethoxy- pentane. All carbons in the Synthesis Target must start as carbons in either ethyne, propyne or methanol. Hint: use your analysis of Product carbons' origins (Part A) to identify possible structure(s) of a precursor that can be converted to the Synthesis Target using one FGI. All carbons in the Synthesis Target must start as carbons in one of the three compounds below. H = -H H = -Me ethyne propyne Synthesis Target 2,4-dimethoxypentane MeOH methanol OMe OMe MeO. OMe C₂H₁₂O₂ Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardDraw the skeletal ("line") structure of the smallest organic molecule that produces potassium 3-hydroxypropanoate when reacted with KOH. Click and drag to start drawing a structure. Sarrow_forward
- draw skeletal structures for the minor products of the reaction.arrow_forward1. Provide missing starting materials, reagents, products. If a product cannot be made, write NP (not possible) in the starting material box. C7H12O Ph HO H 1) 03-78 C 2) Me₂S + Ph .H OH + 2nd stereoisomer OH Ph D + enantiomer cat OsO 4 NMO H2O acetonearrow_forwardPlease note that it is correct and explains it rightly:Indicate the correct option. The proportion of O, C and H in the graphite oxide is:a) Constant, for the quantities of functional groups of acids, phenols, epoxy, etc. its constants.b) Depending on the preparation method, as much oxidant as the graphite is destroyed and it has less oxygen.c) Depends on the structure of the graphic being processed, whether it can be more tridimensional or with larger crystals, or with smaller crystals and with more edges.arrow_forward
- Check the box under each a amino acid. If there are no a amino acids at all, check the "none of them" box under the table. Note for advanced students: don't assume every amino acid shown must be found in nature. ནང་་་ OH HO HO NH2 + NH3 O OIL H-C-CO CH3-CH O C=O COOH COOH + H2N C-H O H2N C H CH3-CH CH2 HO H3N O none of them 口 CH3 CH2 OH Хarrow_forwardWhat is the systematic name of the product P of this chemical reaction? 010 HO-CH2-CH2-C-OH ☐ + NaOH P+ H2Oarrow_forward1. Provide missing starting materials, reagents, products. If a product cannot be made, write NP (not possible) in the starting material box. a) C10H12 Ph OMe AcOHg+ + enantiomer Br C6H10O2 + enantiomerarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY