Explanation Formula used: Molality = Moles of solute mass of solvent in kg Molarity = Moles of solute litre of solution Calculation: As given that 50 mL of 2.238 m H 2 SO 4 with solution density = 1.1243g/ml Suppose the moles of H 2 SO 4 = x moles As given that 1 mL of solution has a mass of 1.1243 g Thus, 50 mL of solution = (50 mL × 1 .1243 g/mL) = 56 .22 g So, the mass of sulphuric acid ( H 2 SO 4 ) = moles × molar mass = x × 98.08 g/mol Now, the mass of solvent = Mass of Solution - Mass of sulphuric acid = 56 .22 g - 98 .08 x As we know the below formula is of Molality Molality = ( Mass of Solute Molar Mass ) × ( 1000 Mass of solvent ) 2.238 m = 98.08 x 98 .08 g/mol × ( 1000 56.22 − 98 x ) x = 56 .22 × 2 .238 1000 + ( 98.08 × 2.238 ) = 0 .103 moles Therefore, moles of sulphuric acid ( H 2 SO 4 ) = 0 Interpretation Introduction To determine: Whether the more precipitate will be obtained or not when more H 2 SO 4 solution is added to the filtrate.

7th Edition

ISBN: 9780321943170

Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson

Publisher: PEARSON

See similar textbooks

Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to a…

Videos

Question

Chapter 12, Problem 12.148CP

Interpretation Introduction

To determine:

The mass of precipitate in grams.

Interpretation Introduction

To determine:

Whether the more precipitate will be obtained or not when more H2SO4 solution is added to the filtrate.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12, Problem 12.147CP

Chapter 12, Problem 12.149CP

Students have asked these similar questions

What are the IUPAC Names of all the compounds in the picture?

1) a) Give the dominant Intermolecular Force (IMF) in a sample of each of the following compounds. Please show your work. (8) SF2, CH,OH, C₂H₂ b) Based on your answers given above, list the compounds in order of their Boiling Point from low to high. (8)

19.78 Write the products of the following sequences of reactions. Refer to your reaction road- maps to see how the combined reactions allow you to "navigate" between the different functional groups. Note that you will need your old Chapters 6-11 and Chapters 15-18 roadmaps along with your new Chapter 19 roadmap for these. (a) 1. BHS 2. H₂O₂ 3. H₂CrO4 4. SOCI₂ (b) 1. Cl₂/hv 2. KOLBU 3. H₂O, catalytic H₂SO4 4. H₂CrO4 Reaction Roadmap An alkene 5. EtOH 6.0.5 Equiv. NaOEt/EtOH 7. Mild H₂O An alkane 1.0 2. (CH3)₂S 3. H₂CrO (d) (c) 4. Excess EtOH, catalytic H₂SO OH 4. Mild H₂O* 5.0.5 Equiv. NaOEt/EtOH An alkene 6. Mild H₂O* A carboxylic acid 7. Mild H₂O* 1. SOC₁₂ 2. EtOH 3.0.5 Equiv. NaOEt/E:OH 5.1.0 Equiv. NaOEt 6. NH₂ (e) 1. 0.5 Equiv. NaOEt/EtOH 2. Mild H₂O* Br (f) i H An aldehyde 1. Catalytic NaOE/EtOH 2. H₂O*, heat 3. (CH,CH₂)₂Culi 4. Mild H₂O* 5.1.0 Equiv. LDA Br An ester 4. NaOH, H₂O 5. Mild H₂O* 6. Heat 7. MgBr 8. Mild H₂O* 7. Mild H₂O+

Chapter 12 Solutions

Chemistry (7th Edition)

Ch. 12 - Prob. 12.1P Ch. 12 - Prob. 12.2A Ch. 12 - Prob. 12.3P Ch. 12 - Prob. 12.4A Ch. 12 - PRACTICE 12.5 A 50.0 mL sample of drinking water...Ch. 12 - APPLY 12.6 The legal limit for human exposure to...Ch. 12 - PRACTICE 12.7 What mass in grams of a 0.500 m...Ch. 12 - APPLY 12.8 What is the molality of a solution...Ch. 12 - PRACTICE 12.9 The density at 20°C of a 0.500 M...Ch. 12 - APPLY 12.10 The density at 20°C of a 0.258 m...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The mass of precipitate in grams.