(a) Interpretation: The correct band picture for diamond, silicon, silicon doped with Al , and white tin should be determined. Concept introduction: The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

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Answer 1

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Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

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Done 11:14 ⚫ worksheets.beyondlabz.com 5 (a). Using the peak information you listed in the tables for both structures, assign each peak to that portion of the structure that produces the peak in the NMR spectrum. Draw this diagram on your own sheet of paper and attach the sketch of your drawing to this question. Question 6 5 (b). Using the peak information you listed in the tables for both structures, assign each peak to that portion of the structure that produces the peak in the NMR spectrum. Draw this diagram on your own sheet of paper and attach the sketch of your drawing to this question. Question 7 6. Are there any differences between the spectra you obtained in Beyond Labz and the predicted spectra? If so, what were the differences? <

2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled** Peak Chemical Shift (d) 5.7 1 Multiplicity multiplate .......... 5.04 double of doublet 2 4.98 double of doublet 3 4.05 doublet of quartet 4 5 LO 3.80 quartet 1.3 doublet 6 Peak Chemical Shift (d) Multiplicity

Interpreting NMR spectra is a skill that often requires some amount of practice, which, in turn, necessitates access to a collection of NMR spectra. Beyond Labz Organic Synthesis and Organic Qualitative Analysis have spectral libraries containing over 700 1H NMR spectra. In this assignment, you will take advantage of this by first predicting the NMR spectra for two closely related compounds and then checking your predictions by looking up the actual spectra in the spectra library. After completing this assignment, you may wish to select other compounds for additional practice. 1. Write the IUPAC names for the following two structures: Question 2 Question 3 2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled**

Answer 2

Question

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

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Answer 3

Question

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

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Answer 4

Question

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

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Answer 5

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Answer 6

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Answer 7

Chapter 12, Problem 12.10A

Interpretation Introduction

(a)

Interpretation:

The correct band picture for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The correct order of electrical conductivity for diamond, silicon, silicon doped with Al, and white tin should be determined.

Concept introduction:

The band theory is used to explain hardness, electrical conductivity, melting point for different metals. It can be explained as a theory related to set of MOs that have very less energy difference between them. These sets of MOs are also known as bands. Melting point of any metal depends on occupancy of both MOs, bonding and antibonding. When the electron from bonding MO can be excessed easily relative to antibonding MO electrons, then melting point metal is higher.

Answer 10

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Answer 13

Ch. 12 - Calcium metal crystallizes in a cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - The density of a sample of metal "as measured to...Ch. 12 - Zinc sulfide crystallizes in the following cubic...Ch. 12 - Prob. 12.6A Ch. 12 - Prob. 12.7P Ch. 12 - Prob. 12.8A Ch. 12 - Prob. 12.9P Ch. 12 - Prob. 12.10A

Solution Summary: The author explains that the band theory is used to explain hardness, electrical conductivity, melting point for different metals.

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Chapter 12 Solutions