Concept explainers
(a)
Interpretation:
The IUPAC name for the given cycloalkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
The IUPAC name for cycloalkane can be obtained simply by adding prefix cyclo- before the
(b)
Interpretation:
The IUPAC name for the given cycloalkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The IUPAC name for cycloalkane can be obtained simply by adding prefix cyclo- before the alkane name which corresponds to the total number of carbon atoms that are present in the ring. To name a cycloalkane, the first step is to find the longest carbon chain that makes a cyclic ring without any unsaturation. The next step is to identify the substituents that are present in the cyclic ring structure. The numbering has to be given in a way that the substituents get the least numbering.
(c)
Interpretation:
The IUPAC name for the given cycloalkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The IUPAC name for cycloalkane can be obtained simply by adding prefix cyclo- before the alkane name which corresponds to the total number of carbon atoms that are present in the ring. To name a cycloalkane, the first step is to find the longest carbon chain that makes a cyclic ring without any unsaturation. The next step is to identify the substituents that are present in the cyclic ring structure. The numbering has to be given in a way that the substituents get the least numbering.
(d)
Interpretation:
The IUPAC name for the given cycloalkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The IUPAC name for cycloalkane can be obtained simply by adding prefix cyclo- before the alkane name which corresponds to the total number of carbon atoms that are present in the ring. To name a cycloalkane, the first step is to find the longest carbon chain that makes a cyclic ring without any unsaturation. The next step is to identify the substituents that are present in the cyclic ring structure. The numbering has to be given in a way that the substituents get the least numbering.
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- The emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…arrow_forwardSteps and explanation pleasearrow_forwardSteps and explanation to undertand concepts.arrow_forward
- Nonearrow_forward7. Draw a curved arrow mechanism for the following reaction. HO cat. HCI OH in dioxane with 4A molecular sievesarrow_forwardTry: Convert the given 3D perspective structure to Newman projection about C2 - C3 bond (C2 carbon in the front). Also, show Newman projection of other possible staggered conformers and circle the most stable conformation. Use the template shown. F H3C Br Harrow_forward
- Nonearrow_forward16. Consider the probability distribution p(x) = ax", 0 ≤ x ≤ 1 for a positive integer n. A. Derive an expression for the constant a, to normalize p(x). B. Compute the average (x) as a function of n. C. Compute σ2 = (x²) - (x)², the variance of x, as a function of n.arrow_forward451. Use the diffusion model from lecture that showed the likelihood of mixing occurring in a lattice model with eight lattice sites: Case Left Right A B C Permeable Barrier → and show that with 2V lattice sites on each side of the permeable barrier and a total of 2V white particles and 2V black particles, that perfect de-mixing (all one color on each side of the barrier) becomes increasingly unlikely as V increases.arrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning