STAT TECH IN BUSINESS & ECON AC
18th Edition
ISBN: 9781264731657
Author: Lind
Publisher: MCG
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Question
Chapter 12, Problem 11E
a.
To determine
Obtain the null and the alternative hypotheses.
b.
To determine
Give the decision rule.
c.
To determine
Find the values of SST, SSE and SS total.
d.
To determine
Find an ANOVA table.
e.
To determine
Find the decision regarding the null hypothesis.
f.
To determine
Check whether there is significant difference between treatment 1 and treatment 2, if null hypothesis is rejected by using the 95% level of confidence.
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For an ANOVA comparing three treatment conditions, what is stated by the null hypothesis (H0)?
a. There are no differences between any of the population means.
b. At least one of the three population means is different from another mean.
c. All three of the population means are different from each other.
d. None of the other choices is correct.
make it so i could copy and paste it
Test the claim that the proportion of people who own cats is significantly different than 50% at the 0.01 significance level.The null and alternative hypothesis would be:
H0:p=0.5H0:p=0.5H1:p≠0.5H1:p≠0.5
H0:μ=0.5H0:μ=0.5H1:μ≠0.5H1:μ≠0.5
H0:p≤0.5H0:p≤0.5H1:p>0.5H1:p>0.5
H0:μ≥0.5H0:μ≥0.5H1:μ<0.5H1:μ<0.5
H0:p≥0.5H0:p≥0.5H1:p<0.5H1:p<0.5
H0:μ≤0.5H0:μ≤0.5H1:μ>0.5H1:μ>0.5
The test is:
left-tailed
two-tailed
right-tailed
Based on a sample of 700 people, 43% owned catsThe p-value is: (to 2 decimals)Based on this we:
Reject the null hypothesis
Fail to reject the null hypothesis
Chapter 12 Solutions
STAT TECH IN BUSINESS & ECON AC
Ch. 12 - Steele Electric Products Inc. assembles cell...Ch. 12 - What is the critical F value when the sample size...Ch. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 2SRCh. 12 - Prob. 7ECh. 12 - Prob. 8E
Ch. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 3SRCh. 12 - Prob. 11ECh. 12 - The following are six observations collected from...Ch. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 4SRCh. 12 - Prob. 15ECh. 12 - For exercises 15 and 16, conduct a test of...Ch. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 5SRCh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23CECh. 12 - Prob. 24CECh. 12 - Prob. 25CECh. 12 - Prob. 26CECh. 12 - In an ANOVA table, the MSE is equal to 10. Random...Ch. 12 - Prob. 28CECh. 12 - Prob. 29CECh. 12 - Prob. 30CECh. 12 - Prob. 31CECh. 12 - Prob. 32CECh. 12 - Prob. 33CECh. 12 - Prob. 34CECh. 12 - Prob. 35CECh. 12 - Prob. 36CECh. 12 - Prob. 37CECh. 12 - Prob. 38CECh. 12 - Prob. 39CECh. 12 - Prob. 40CECh. 12 - Prob. 41CECh. 12 - Prob. 42CECh. 12 - Prob. 43CECh. 12 - Prob. 44CECh. 12 - Prob. 45CECh. 12 - Prob. 46CECh. 12 - Prob. 47CECh. 12 - Prob. 48CECh. 12 - Prob. 50DACh. 12 - Prob. 51DACh. 12 - Prob. 1PCh. 12 - Prob. 2PCh. 12 - Prob. 3PCh. 12 - Prob. 4PCh. 12 - Prob. 5PCh. 12 - Prob. 6PCh. 12 - Prob. 7PCh. 12 - Prob. 1CCh. 12 - Prob. 2CCh. 12 - Prob. 1.1PTCh. 12 - The likelihood of rejecting a true null hypothesis...Ch. 12 - Prob. 1.3PTCh. 12 - Prob. 1.4PTCh. 12 - Prob. 1.5PTCh. 12 - Prob. 1.6PTCh. 12 - In a two-tailed test, the rejection region is...Ch. 12 - Prob. 1.8PTCh. 12 - Prob. 1.9PTCh. 12 - Prob. 1.10PTCh. 12 - Prob. 2.1PTCh. 12 - Prob. 2.2PTCh. 12 - Prob. 2.3PT
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