MCAT-Style Passage Problems Thermal Properties of the Oceans Seasonal temperature changes in the ocean only affect the top layer of water, to a depth of 500 0m or so. This “mixed” layer is thermally isolated from the cold, deep water below. The average temperature of this top layer of the world’s oceans, which has area 3.6 × 10 8 km 2 , is approximately 17°C . In addition to seasonal temperature changes, the oceans have experienced an overall warming trend over the last century that is expected to continue as the earth’s climate changes. A warmer ocean means a larger volume of water; the oceans will rise. Suppose the average temperature of the top layer of the world's oceans were to increase from a temperature T i ; to a temperature T f . The area of the oceans will not change, as this is fixed by the size of the ocean basin, so any thermal expansion of the water will cause the water level to rise, as shown in Figure P12.109 . The original volume is the product of the original depth and the surface area, V i = Ad i . The change in volume is given by Δ V = A Δ d . Figure P12.109 If the top 500 m of ocean water increased in temperature from 17°C to 18°C, what would be the resulting rise in ocean height? A. 0.11 m B. 0.22 m C. 0.44 m D. 0.88 m
MCAT-Style Passage Problems Thermal Properties of the Oceans Seasonal temperature changes in the ocean only affect the top layer of water, to a depth of 500 0m or so. This “mixed” layer is thermally isolated from the cold, deep water below. The average temperature of this top layer of the world’s oceans, which has area 3.6 × 10 8 km 2 , is approximately 17°C . In addition to seasonal temperature changes, the oceans have experienced an overall warming trend over the last century that is expected to continue as the earth’s climate changes. A warmer ocean means a larger volume of water; the oceans will rise. Suppose the average temperature of the top layer of the world's oceans were to increase from a temperature T i ; to a temperature T f . The area of the oceans will not change, as this is fixed by the size of the ocean basin, so any thermal expansion of the water will cause the water level to rise, as shown in Figure P12.109 . The original volume is the product of the original depth and the surface area, V i = Ad i . The change in volume is given by Δ V = A Δ d . Figure P12.109 If the top 500 m of ocean water increased in temperature from 17°C to 18°C, what would be the resulting rise in ocean height? A. 0.11 m B. 0.22 m C. 0.44 m D. 0.88 m
Seasonal temperature changes in the ocean only affect the top layer of water, to a depth of 500 0m or so. This “mixed” layer is thermally isolated from the cold, deep water below. The average temperature of this top layer of the world’s oceans, which has area 3.6 × 108 km2, is approximately 17°C.
In addition to seasonal temperature changes, the oceans have experienced an overall warming trend over the last century that is expected to continue as the earth’s climate changes. A warmer ocean means a larger volume of water; the oceans will rise. Suppose the average temperature of the top layer of the world's oceans were to increase from a temperature Ti; to a temperature Tf. The area of the oceans will not change, as this is fixed by the size of the ocean basin, so any thermal expansion of the water will cause the water level to rise, as shown in Figure P12.109. The original volume is the product of the original depth and the surface area, Vi = Adi. The change in volume is given by ΔV = AΔd.
Figure P12.109
If the top 500 m of ocean water increased in temperature from 17°C to 18°C, what would be the resulting rise in ocean height?
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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Chapter 12 Solutions
College Physics: A Strategic Approach (3rd Edition)
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