a) Interpretation: The actual product has to be identified. Concept introduction: Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene . An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction . When two substituents are removed from the molecule in two steps is called E1 reaction . E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene E2 elimination: Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Question

when performing the reaction that involves 2 equivalents of 3-(diethylamino)-phenol and Phthalic anhydride with sulfuric acid and water react to form rhodamine b where the Phthalic anhydride cleaves in acid and how does Excessive Washing (w/ Base) & Subsequent Resonance Structure get affected

Answer 1

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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when performing the reaction that involves 2 equivalents of 3-(diethylamino)-phenol and Phthalic anhydride with sulfuric acid and water react to form rhodamine b where the Phthalic anhydride cleaves in acid and how does Excessive Washing (w/ Base) & Subsequent Resonance Structure get affected

3. The strongest acid of the following compounds is ___.A. p-nitrophenol; B. m-nitrophenol; C. o-chlorophenol;D. p-methoxyphenol; E. o-methylphenol Please explain your steps and thought process. Thank you!

Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4: Cl2(g) + CHCl3(g) HCl(g) + CC₁(g) Use this information to complete the following table. Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and 1.6 mol of CCl4. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little Cl2 and CHCl3. ☐ x10 There will be very little HCI and CCl4. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. HCl(g)+CC14(g) 12 Cl2(9)+CHCl3(9) K = 0 ☐ What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 Cl₂(9)+2CHCl3(9) 2 HCl(9)+2CC₁₁(9) K = ✓ 00. 18 Ar

Answer 2

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 3

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 4

Question

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

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Answer 5

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 6

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 7

Chapter 11.SE, Problem 54AP

Interpretation Introduction

a)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 8

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 9

Interpretation Introduction

b)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 10

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 11

Interpretation Introduction

c)

Interpretation:

The actual product has to be identified.

Concept introduction:

Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the Î²-carbon atom in two steps which leads to the product as an alkene

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Answer 12

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Ch. 11.1 - Prob. 1P Ch. 11.2 - Prob. 2P Ch. 11.2 - Prob. 3P Ch. 11.3 - Prob. 4P Ch. 11.3 - Prob. 5P Ch. 11.3 - Rank the following compounds in order of their...Ch. 11.3 - Organic solvents like benzene, ether, and...Ch. 11.4 - Prob. 8P Ch. 11.4 - Prob. 9P Ch. 11.4 - Prob. 10P

Solution Summary: The author explains that an elimination reaction is removal of two substituents in a molecule and forms alkene.

Chapter 11 Solutions