a)
Interpretation:
The expected product between the
Answer to Problem 21VC
The ethyl chloride undergoes SN2 reaction with Na+SCH3- and NaOH to yield a product.
The product is CH3CH2SCH3, CH3CH2OH.
Here the leaving group is Cl.
The nucleophile is SCH3-,OH.
Hence it undergoes SN2 reaction.
Explanation of Solution
The ethyl chloride undergoes SN2 reaction with Na+SCH3- and NaOH to yield a product.
The product is CH3CH2SCH3, CH3CH2OH.
Here the leaving group is Cl.
The nucleophile is SCH3-,OH.
Hence it undergoes SN2 reaction.
The ethyl chloride undergoes SN2 reaction with Na+SCH3- and NaOH to yield a product.
The product is CH3CH2SCH3, CH3CH2OH.
Here the leaving group is Cl.
The nucleophile is SCH3-,OH.
Hence it undergoes SN2 reaction.
b)
Interpretation:
The expected product between the alkyl halide CH3CH2Cl+Na+SCH3- and NaOH is interpreted.
Answer to Problem 21VC
The alkyl halide undergoes SN1 reaction with Na+SCH3- to yield a SCH3 Substituited product.
The product is shown in the reaction.
In this reaction leaving group is Cl, the nucleophile is SCH3-
Explanation of Solution
The alkyl halide undergoes E1 reaction with NaOH to yield a
The product is shown here
The alkyl halide undergoes SN1reaction with Na+SCH3- to yield a SCH3 Substituited product.
The product is shown in the reaction.
In this reaction leaving group is Cl, the nucleophile is SCH3-
c)
Interpretation:
The expected product between the alkyl halide CH3CH2Cl+Na+SCH3- and NaOH is interpreted.
Answer to Problem 21VC
The benzylchloride undergoes SN1 reaction with Na+SCH3- to yield a product.
The product is shown here.
Here the leaving group is Cl.
The nucleophile is SCH3-Hence it undergoes SN1 reaction.
Explanation of Solution
The benzylchloride undergoes E1 reaction with NaOH to yield a product.
The product is shown here
The benzylchloride undergoes SN1 reaction with Na+SCH3- to yield a product.
The product is shown here.
Here the leaving group is Cl.
The nucleophile is SCH3- Hence it undergoes SN1 reaction.
Want to see more full solutions like this?
Chapter 11 Solutions
Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
- H2O2(aq) +3 I¯(aq) +2 H+(aq) → 13(aq) +2 H₂O(l)· ••• Experiment [H2 O2]o (M) [I]o (M) [H+]。 (M) Initial rate (M/s) 1 0.15 0.15 0.05 0.00012 234 0.15 0.3 0.05 0.00024 0.3 0.15 0.05 0.00024 0.15 0.15 0.1 0.00048 Calculate the overall order of this reaction using the table data.arrow_forwardThe U. S. Environmental Protection Agency (EPA) sets limits on healthful levels of air pollutants. The maximum level that the EPA considers safe for lead air pollution is 1.5 μg/m³ Part A If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung volume of 5.40 L.) ΜΕ ΑΣΦ = 2.35 1013 ? atoms ! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step. No credit lost. Try again.arrow_forwardY= - 0.039 (14.01) + 0.7949arrow_forward
- Suppose 1.76 g of magnesium acetate (Mg (CH3CO2)2) are dissolved in 140. mL of water. Find the composition of the resulting electrolyte solution. In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row. mEq Then, calculate the concentration of each ion in dwrite the concentration in the second column of each row. Be sure you round your answers to the L correct number of significant digits. ion Add Row mEq L x 5arrow_forwardA pdf file of your hand drawn, stepwise mechanisms for the reactions. For each reaction in the assignment, you must write each mechanism three times (there are 10 reactions, so 30 mechanisms). (A) do the work on a tablet and save as a pdf., it is expected to write each mechanism out and NOT copy and paste the mechanism after writing it just once. Everything should be drawn out stepwise and every bond that is formed and broken in the process of the reaction, and is expected to see all relevant lone pair electrons and curved arrows.arrow_forwardNonearrow_forward
- Nonearrow_forwardDraw the structure of the product of the reaction given the IR and MS data. Spectral analysis of the product reveals: MS: M 150, M-15, M-43 CH.COCI AICI, IR: 3150-3000 cm, 2950-2850 cm and 1700 cmarrow_forwardPart II. Identify whether the two protons in blue are homotopic, enantiopic, diasteriotopic, or heterotopic. a) HO b) Bri H HH c) d) H H H Br 0arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning