Explanation Given: The differential equation P L ( t ) = e − k t [ P L ( 0 ) + k ∫ 0 t P i ( x ) e k x d x ] and P i ( x ) is equal to P L ( 0 ) e − p x . Approach: Integrate the equation to get the required result. Calculation: Substitute P i ( x ) by P L ( 0 ) e − p x in the equation (1). P L ( t ) = e − k t [ P L ( 0 ) + k ∫ 0 t P L ( 0 ) e p x e k x d x ] Solve the integration in right hand side of the equation.

2nd Edition

ISBN: 9780321964038

Author: GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher: Pearson Addison Wesley,

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Differential Equations

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Chapter 11.EA, Problem 5EA

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The solution of the differential equation obtained by substituting Pi(x) by PL(0)e−px in equation (1).

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The solution of the differential equation obtained by substituting P i ( x ) by P L ( 0 ) e − p x in equation (1).

Solution Summary: The author explains that the solution of the differential equation is given by substituting P_i(x) by

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To find:

The solution of the differential equation obtained by substituting Pi(x) by PL(0)e−px in equation (1).

Want to see the full answer?

Chapter 11 Solutions

The solution of the differential equation obtained by substituting P i ( x ) by P L ( 0 ) e − p x in equation (1).

Solution Summary: The author explains that the solution of the differential equation is given by substituting P_i(x) by

Concept explainers

Videos

To find: The solution of the differential equation obtained by substituting Pi(x) by PL(0)e−px in equation (1).

Want to see the full answer?

Chapter 11 Solutions

To find:

The solution of the differential equation obtained by substituting Pi(x) by PL(0)e−px in equation (1).