Explanation The following figure shows the saturation pressure-temperature curve. Figure (1) Conclusion: Write the expression for temperature T 1 at point 1. ln ( p sat , 1 ) = A − B T 1 A = ln ( p sat , 1 ) + B T 1 (I) Here, the constants are A and B . Write the expression for temperature T 2 at point 2. ln ( p sat , 2 ) = A − B T 2 (II) Write the expression for temperature T 3 at point 3. ln ( p sat , 3 ) = A − B T 3 (III) Substitute ln ( p sat , 1 ) + B T 1 for A in Equation (II). ln ( p sat , 2 ) = ln ( p sat, 1 ) + ( B T 1 − B T 2 ) ln ( p sat , 2 ) − ln ( p sat, 1 ) = ( B T 1 − B T 2 ) ln ( p sat , 2 ) ln ( p sat, 1 ) = B ( 1 T 1 − 1 T 2 ) (IV) Substitute ln ( p sat, 1 ) + B T 1 for A in Equation (III). ln ( p sat, 3 ) = ln ( p sat, 1 ) + ( B T 1 − B T 3 ) ln ( p sat , 3 ) − ln ( p sat, 1 ) = ( B T 1 − B T 3 ) ln ( p sat, 3 ) ln ( p sat, 1 ) = B ( 1 T 1 − 1 T 3 ) (V) Divide Equation (IV) with Equation (V)

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 11.9, Problem 42P

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The derivation of (psat, 3psat, 1)=(psat, 2psat, 1)τ.

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Chapter 11.9, Problem 39P

Chapter 11.9, Problem 43P

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The derivation of ( p sat, 3 p sat, 1 ) = ( p sat, 2 p sat, 1 ) τ .

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The derivation of (psat, 3psat, 1)=(psat, 2psat, 1)τ.

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