Shown again is the table indicating the marital status of the U.S. population in 2015. Numbers in the table are expressed in millions. Use the data in the table to solve Exercises 65-76. Express probabilities as simplified fractions and as decimals rounded to the nearest hundredth. MARITAL STATUS OF THE U.S. POPULATION, AGES 15 OR OLDER, 2015, IN MILLIONS Married Never Married Divorced Widowed Total Male 66 43 11 3 123 Female 67 38 15 11 131 Total 133 81 26 14 254 If one person is selected from the population described in the table, find the Probability, that the person 72. is male given that this person is divorced. 15 26 ≈ 0.58
Shown again is the table indicating the marital status of the U.S. population in 2015. Numbers in the table are expressed in millions. Use the data in the table to solve Exercises 65-76. Express probabilities as simplified fractions and as decimals rounded to the nearest hundredth. MARITAL STATUS OF THE U.S. POPULATION, AGES 15 OR OLDER, 2015, IN MILLIONS Married Never Married Divorced Widowed Total Male 66 43 11 3 123 Female 67 38 15 11 131 Total 133 81 26 14 254 If one person is selected from the population described in the table, find the Probability, that the person 72. is male given that this person is divorced. 15 26 ≈ 0.58
Solution Summary: The author explains the formula used to calculate the probability that a person is female, given that they are divorced.
Shown again is the table indicating the marital status of the U.S. population in 2015. Numbers in the table are expressed in millions. Use the data in the table to solve Exercises 65-76. Express probabilities as simplified fractions and as decimals rounded to the nearest hundredth.
MARITAL STATUS OF THE U.S. POPULATION, AGES 15 OR OLDER, 2015, IN MILLIONS
Married
Never Married
Divorced
Widowed
Total
Male
66
43
11
3
123
Female
67
38
15
11
131
Total
133
81
26
14
254
If one person is selected from the population described in the table, find the Probability, that the person
72. is male given that this person is divorced.
15
26
≈
0.58
1.
2.
Show that the following are not logically equivalent by finding a counterexample:
(p^q) →r and
(db) V (d←d)
Show that the following is not a contradiction by finding a counterexample:
(pV-q) AqA (pv¬q Vr)
3.
Here is a purported proof that (pq) ^ (q → p) = F:
(db) v (bd) = (db) v (bd)
=(qVp) A (g→p)
= (¬¬q V ¬p) ^ (q→ p)
(db) V (db) =
=¬(a→p)^(a→p)
= (gp) ^¬(a → p)
=F
(a) Show that (pq) ^ (q→p) and F are not logically equivalent by finding a counterex-
ample.
(b) Identify the error(s) in this proof and justify why they are errors. Justify the other steps
with their corresponding laws of propositional logic.
Question 2: When John started his first job, his first end-of-year salary was $82,500. In the following years, he received salary raises as shown in the following table.
Fill the Table: Fill the following table showing his end-of-year salary for each year. I have already provided the end-of-year salaries for the first three years. Calculate the end-of-year salaries for the remaining years using Excel. (If you Excel answer for the top 3 cells is not the same as the one in the following table, your formula / approach is incorrect) (2 points)
Geometric Mean of Salary Raises: Calculate the geometric mean of the salary raises using the percentage figures provided in the second column named “% Raise”. (The geometric mean for this calculation should be nearly identical to the arithmetic mean. If your answer deviates significantly from the mean, it's likely incorrect. 2 points)
Hint for the first part of question 2: To assist you with filling out the table in the first part of the question,…
Chapter 11 Solutions
Thinking Mathematically, Books a la Carte Edition plus MyLab Math with Pearson eText -- Access Card Package, 4/e (7th Edition)
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