Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 11.7, Problem 11.60QAP
Interpretation Introduction
Interpretation: Temperature of 525 ml CO2having mass of 0.226gram and pressure of 455mmHg
Conceptual Introduction: The
Equation as follows-
PV = nRT
Where, P = pressure of gas
V = volume of gas
N= No. of moles of gas (amount of substance in gas)
R = Universal gas constant
The gas constant R has a value 8.314J/mole Kelvin
T = Temperature in Kelvin
T(Kelvin) = T(Celsius) + 273.15 (Conversion from kelvin to Celsius)
Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass
Given:
Volume = 525 ml
Pressure = 455 mmHg
Mass = 0.226 grams
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Chapter 11 Solutions
Basic Chemistry (5th Edition)
Ch. 11.1 - Prob. 11.1QAPCh. 11.1 - Prob. 11.2QAPCh. 11.1 - Prob. 11.3QAPCh. 11.1 - Prob. 11.4QAPCh. 11.1 - Prob. 11.5QAPCh. 11.1 - Prob. 11.6QAPCh. 11.1 - Prob. 11.7QAPCh. 11.1 - Prob. 11.8QAPCh. 11.2 - Why do scuba divers need to exhale air when they...Ch. 11.2 - Why does a sealed bag of chips expand when you...
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