(A) If 120 scores are chosen from a normal distribution with mean and standard deviation 8 , how many scores x would be expected to satisfy 67 ≤ x ≤ 83 (B) Usea graphing calculator to generate 120 scores from the normal distribution with mean 75 and standard deviation 8 . Determine the number of scores x such that 67 ≤ x ≤ 83 , and compare your results with the answerto part (A).
(A) If 120 scores are chosen from a normal distribution with mean and standard deviation 8 , how many scores x would be expected to satisfy 67 ≤ x ≤ 83 (B) Usea graphing calculator to generate 120 scores from the normal distribution with mean 75 and standard deviation 8 . Determine the number of scores x such that 67 ≤ x ≤ 83 , and compare your results with the answerto part (A).
Solution Summary: The author calculates the number of scores that satisfies 67le xl 83 if 120 scores are chosen from a normal distribution with mean as 75 and standard deviation as
(A) If
120
scores are chosen from a normal distribution with mean and standard deviation
8
, how many scores
x
would be expected to satisfy
67
≤
x
≤
83
(B) Usea graphing calculator to generate
120
scores from the normal distribution with mean
75
and standard deviation
8
. Determine the number of scores
x
such that
67
≤
x
≤
83
, and compare your results with the answerto part (A).
Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.
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Chapter 11 Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (13th Edition)
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