(a)
Interpretation:
The predominant molecular force present in
Concept Introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion (Induced dipole-induced dipole forces)
- Dipole-dipole
- Hydrogen bonding
(b)
Interpretation:
The predominant molecular force present in liquid
Concept Introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion
- Dipole-dipole
- Hydrogen bonding
(c)
Interpretation:
The predominant molecular force present in
Concept introduction:
Intermolecular forces in a molecule are the important factor which is responsible for the physical changes of the molecule.
The intermolecular forces in gases are negligibly small and the forces are comparatively stronger in liquids and the intermolecular forces are highest in solids.
The stronger the intermolecular forces, closer will be the molecules in contact and thus higher will be the boiling point and melting point of the substance.
Three types of intermolecular forces:
- London dispersion
- Dipole-dipole
- Hydrogen bonding
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Chapter 11 Solutions
Chemistry and Chemical Reactivity - AP Edition
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- Can you help me understand the CBC method on metal bridging by looking at this problem?arrow_forwardA partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forward
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