Explanation Calculation: The summary in Exercise 12 is such that n = 20 , s e = 4.65 , ∑ ( x − x ¯ ) 2 = 118.26 , b 1 = 1.62 . Denote x as the explanatory variable and y as the outcome variable. Denote β 1 as slope of the population regression line. Step 1: The slope of the computed regression line is given as b 1 = 1.62 . Step 2: The given test hypotheses are: Null hypothesis: H 1 : β 1 > 0 That is, there is no significant linear relationship between the explanatory variable and the outcome variable . Alternate hypothesis: H 1 : β 1 ≠ 0 That is, there is significant positive linear relationship between the explanatory variable and the outcome variable . Step 3: It is given that the level of significance is 0.05. Step 4: From Exercise 12, the standard error of b 1 is obtained as s b = 0.4276 . Step 5: Test statistic: The t- test statistic is: t = b 1 s b , Where, b 1 is the slope of the computed regression line, s b is the standard error of b 1 . Thus, t = b 1 s b = 1.62 0.4276 ≈ 3.79. From Exercise 12, the degrees of freedom is obtained as df = 18 . Critical value Method: Step 6: The critical value for the right-tailed test at level of significance 0

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Chapter 11.3, Problem 14E

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Test the null hypotheses H0:β1=0 versus H1:β1>0 at the level of significance α=0.05.

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Chapter 11.3, Problem 13E

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Chapter 11 Solutions

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Ch. 11.1 - Prob. 11E Ch. 11.1 - Prob. 12E Ch. 11.1 - Prob. 13E Ch. 11.1 - Prob. 14E Ch. 11.1 - Prob. 15E Ch. 11.1 - Prob. 16E Ch. 11.1 - Prob. 17E Ch. 11.1 - Prob. 18E Ch. 11.1 - Prob. 19E Ch. 11.1 - Prob. 20E Ch. 11.1 - Prob. 21E Ch. 11.1 - Prob. 22E Ch. 11.1 - Prob. 23E Ch. 11.1 - Prob. 24E Ch. 11.1 - Prob. 25E Ch. 11.1 - Prob. 26E Ch. 11.1 - Prob. 27E Ch. 11.1 - In Exercises 25–30, determine whether the...Ch. 11.1 - Prob. 29E Ch. 11.1 - Prob. 30E Ch. 11.1 - Prob. 31E Ch. 11.1 - Prob. 32E Ch. 11.1 - 33. Pass the ball: The NFL Scouting Combine is an...Ch. 11.1 - 34. Carbon footprint: Carbon dioxide (CO2) is...Ch. 11.1 - 35. Foot temperatures: Foot ulcers are a common...Ch. 11.1 - Prob. 36E Ch. 11.1 - Prob. 37E Ch. 11.1 - Prob. 38E Ch. 11.1 - Prob. 39E Ch. 11.1 - Prob. 40E Ch. 11.1 - Prob. 41E Ch. 11.1 - Prob. 42E Ch. 11.1 - Prob. 43E Ch. 11.2 - 1. The following table presents the percentage of...Ch. 11.2 - 2. At the final exam in a statistics class, the...Ch. 11.2 - 3. For each of the following plots, interpret the...Ch. 11.2 - Prob. 4CYU Ch. 11.2 - Prob. 5E Ch. 11.2 - In Exercises 5–7, fill in each blank with the...Ch. 11.2 - Prob. 7E Ch. 11.2 - Prob. 8E Ch. 11.2 - In Exercises 8–12, determine whether the statement...Ch. 11.2 - Prob. 10E Ch. 11.2 - Prob. 11E Ch. 11.2 - Prob. 12E Ch. 11.2 - Prob. 13E Ch. 11.2 - Prob. 14E Ch. 11.2 - Prob. 15E Ch. 11.2 - Prob. 16E Ch. 11.2 - Prob. 17E Ch. 11.2 - Prob. 18E Ch. 11.2 - Prob. 19E Ch. 11.2 - Prob. 20E Ch. 11.2 - Prob. 21E Ch. 11.2 - Prob. 22E Ch. 11.2 - Prob. 23E Ch. 11.2 - Prob. 24E Ch. 11.2 - Prob. 25E Ch. 11.2 - Prob. 26E Ch. 11.2 - 27. Blood pressure: A blood pressure measurement...Ch. 11.2 - Prob. 28E Ch. 11.2 - 29. Interpreting technology: The following display...Ch. 11.2 - Prob. 30E Ch. 11.2 - Prob. 31E Ch. 11.2 - Prob. 32E Ch. 11.2 - Prob. 33E Ch. 11.2 - Prob. 34E Ch. 11.2 - Prob. 35E Ch. 11.3 - Prob. 1CYU Ch. 11.3 - Prob. 2CYU Ch. 11.3 - Prob. 3CYU Ch. 11.3 - Prob. 4CYU Ch. 11.3 - Prob. 5CYU Ch. 11.3 - Prob. 6CYU Ch. 11.3 - Prob. 7E Ch. 11.3 - Prob. 8E Ch. 11.3 - Prob. 9E Ch. 11.3 - Prob. 10E Ch. 11.3 - Prob. 11E Ch. 11.3 - Prob. 12E Ch. 11.3 - Prob. 13E Ch. 11.3 - Prob. 14E Ch. 11.3 - Prob. 15E Ch. 11.3 - Prob. 16E Ch. 11.3 - Prob. 17E Ch. 11.3 - Prob. 18E Ch. 11.3 - Calories and protein: The following table presents...Ch. 11.3 - Prob. 20E Ch. 11.3 - Butterfly wings: Do larger butterflies live...Ch. 11.3 - Blood pressure: A blood pressure measurement...Ch. 11.3 - Prob. 23E Ch. 11.3 - Prob. 24E Ch. 11.3 - Getting bigger: Concrete expands both horizontally...Ch. 11.3 - Prob. 26E Ch. 11.3 - Prob. 27E Ch. 11.3 - Prob. 28E Ch. 11.3 - Prob. 29E Ch. 11.3 - Prob. 30E Ch. 11.3 - Prob. 31E Ch. 11.4 - Prob. 1CYU Ch. 11.4 - Prob. 2CYU Ch. 11.4 - Prob. 3E Ch. 11.4 - Prob. 4E Ch. 11.4 - Prob. 5E Ch. 11.4 - Prob. 6E Ch. 11.4 - Prob. 7E Ch. 11.4 - Prob. 8E Ch. 11.4 - Prob. 9E Ch. 11.4 - Prob. 10E Ch. 11.4 - Calories and protein: Use the data in Exercise 19...Ch. 11.4 - Prob. 12E Ch. 11.4 - Butterfly wings: Use the data in Exercise 21 in...Ch. 11.4 - Prob. 14E Ch. 11.4 - Prob. 15E Ch. 11.4 - Prob. 16E Ch. 11.4 - Prob. 17E Ch. 11.4 - Prob. 18E Ch. 11.4 - Prob. 19E Ch. 11.4 - Prob. 20E Ch. 11.4 - Prob. 21E Ch. 11 - Prob. 1CQ Ch. 11 - Prob. 2CQ Ch. 11 - Prob. 3CQ Ch. 11 - Prob. 4CQ Ch. 11 - Prob. 5CQ Ch. 11 - Prob. 6CQ Ch. 11 - Prob. 7CQ Ch. 11 - Prob. 8CQ Ch. 11 - Prob. 9CQ Ch. 11 - Prob. 10CQ Ch. 11 - Prob. 11CQ Ch. 11 - Prob. 12CQ Ch. 11 - Prob. 13CQ Ch. 11 - Prob. 14CQ Ch. 11 - Prob. 15CQ Ch. 11 - Prob. 1RE Ch. 11 - Prob. 2RE Ch. 11 - Prob. 3RE Ch. 11 - Prob. 4RE Ch. 11 - Prob. 5RE Ch. 11 - Prob. 6RE Ch. 11 - Prob. 7RE Ch. 11 - Prob. 8RE Ch. 11 - Prob. 9RE Ch. 11 - Prob. 10RE Ch. 11 - Prob. 11RE Ch. 11 - Prob. 12RE Ch. 11 - Prob. 13RE Ch. 11 - Interpret technology: The following TI-84 Plus...Ch. 11 - Prob. 15RE Ch. 11 - Prob. 1WAI Ch. 11 - Prob. 2WAI Ch. 11 - Prob. 3WAI Ch. 11 - Prob. 4WAI Ch. 11 - Prob. 5WAI Ch. 11 - Prob. 6WAI Ch. 11 - Prob. 7WAI Ch. 11 - Prob. 1CS Ch. 11 - Prob. 2CS Ch. 11 - Prob. 3CS Ch. 11 - Prob. 4CS Ch. 11 - Prob. 5CS Ch. 11 - Prob. 6CS Ch. 11 - Prob. 7CS Ch. 11 - Prob. 8CS Ch. 11 - Prob. 9CS Ch. 11 - Prob. 10CS Ch. 11 - Prob. 11CS

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Test the null hypotheses H 0 : β 1 = 0 versus H 1 : β 1 &gt; 0 at the level of significance α = 0.05 .

Test the null hypotheses H0:β1=0 versus H1:β1>0 at the level of significance α=0.05.

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Chapter 11 Solutions

Test the null hypotheses H 0 : β 1 = 0 versus H 1 : β 1 > 0 at the level of significance α = 0.05 .