Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

11th Edition

ISBN: 9780134765785

Author: Hal Saunders

Publisher: PEARSON

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Textbook Question

Chapter 11.2, Problem 8CE

C. Practical Applications. (Round to the nearest hundredth.)

Electrical Trades If P = RI² for a direct current circuit, find I (current in amperes) if

(a) The power (P) is 405 watts and the resistance (R) is 5 ohms.
(b) The power is 800 watts and the resistance is 15 ohms.

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Chapter 11.2, Problem 7CE

Chapter 11.2, Problem 9CE

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Chapter 11 Solutions

Mathematics for the Trades: A Guided Approach, Books a la Carte edition (11th Edition)

Ch. 11.1 - Simplify: 2(3 + 2y) 3y Ch. 11.1 - Prob. 2LC Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Prob. 5AE Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Prob. 7AE Ch. 11.1 - Solve each of the following systems of equations...

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C. Practical Applications. (Round to the nearest hundredth.) Electrical Trades If P = RI 2 for a direct current circuit, find I (current in amperes) if (a) The power ( P ) is 405 watts and the resistance ( R ) is 5 ohms. (b) The power is 800 watts and the resistance is 15 ohms.

Solution Summary: The power can be calculated using a formula P=RI2, where power and resistance are 405 watts and 5 ohms, respectively.

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Chapter 11 Solutions