Preliminary data analyses and other information indicate that you can reasonably assume that, in Exercises 11.63–11.68, the variable under consideration is
11.64 Pulmonary Hypertension. In the paper “Persistent Pulmonary Hypertension of the Neonate and Asymmetric Growth Restriction” (Obstetrics & Gynecology, Vol. 91, No. 3, pp. 336–341), M. Williams et al. reported on a study of characteristics of neonates. Infants treated for pulmonary hypertension, called the PH group, were compared with those not so treated, called the control group. One of the characteristics measured was head circumference. The following data, in centimeters (cm), are based on the results obtained by the researchers.
Do the data provide sufficient evidence to conclude that variation in head circumference differs among neonates treated for pulmonary hypertension and those not so treated? Perform an F-test at the 5% significance level. (Note: s1, = 1.907 and s2 = 1.594.)
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Introductory Statistics (10th Edition)
- Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows. Previous Year Occupied Rooms Total Rooms Current Year 1,505 1,750 1,577 1,900 a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Let P₁ = population proportion of rooms occupied for current year P2 = population proportion of rooms occupied for previous year Ho: P1 P2 less than or equal to 0 Ha P₁ P2 greater than 0 b. What is the estimated proportion of hotel rooms occupied each year (to 2 decimals)? Current year Previous Year c. Conduct a hypothesis test. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. p-value = Using a 0.05 level of significance, what is your conclusion? We can conclude that there has been an…arrow_forwardTourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows. Current Year Previous Year Occupied Rooms 1,360 1,386 Total Rooms 1,700 1,800 a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Let pi = population proportion of rooms occupied for current year Pa= population proportion of rooms occupied for previous year Ho : Pi - Pa H.: Pi - P2 Select your answer Select your answer b. What is the estimated proportion of hotel rooms occupied each year (to 2 decimals)? Current year Previous Year c. Conduct a hypothesis test. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. p-value - Using a 0.05 level of significance, what is your conclusion? We Select your answer- vthat there has…arrow_forwardTourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel). Hotel occupancy data for February in two consecutive years are as follows. Current Year Previous Year OccupiedRooms 1,470 1,458 TotalRooms 1,750 1,800 (a) Formulate the hypothesis test that can be used to determine if there has been an increase in the proportion of rooms occupied over the one-year period. (Let p1 = population proportion of rooms occupied for current year and p2 = population proportion of rooms occupied for previous year.) H0: p1 − p2 ≤ 0 Ha: p1 − p2 > 0 H0: p1 − p2 ≠ 0 Ha: p1 − p2 = 0 H0: p1 − p2 = 0 Ha: p1 − p2 ≠ 0 H0: p1 − p2 < 0 Ha: p1 − p2 = 0 H0: p1 − p2 ≥ 0 Ha: p1 − p2 < 0 (b) What is the estimated proportion of hotel rooms occupied each year? current ( ) previous ( ) (c) Calculate the test statistic. (Round your answer to two decimal places.) (…arrow_forward
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- A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use α = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. What are the hypotheses? Ho: dis - Select your answer - H₂: Hd is-Select your answer - Compute a (to 3 decimals). Compute & (to 1 decimal). What is the p-value? The p-value is - Select your answer - What is your decision? - Select your answer - Individual 1 2 3 4 Purchase Rating Before 5 4 After 7 6 8 5 8 3 Individual 5 6 7 8 Purchase Rating Before 4 After 3 9 6 6…arrow_forwardA market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use α = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Individual O Ho: Md ≤0 Ha: Md = 0 O Ho: Md ≤0 Ha: Md > 0 O Ho: Md = 0 1 Ha: Md 0 2 3 4 5 6 7 8 Purchase Rating After Before 6 6 7 4 3 7 6 5 4 8 3 State the null and alternative hypotheses. (Use μ = mean rating after - mean rating before.) O Ho: μg 0 Ha: Md = 0 7 8 5 7 Ho: Md > O Ha: Md ≤ 0 Calculate the value of the test statistic. (Round your answer to three…arrow_forwardA market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use α = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Ha: a: Md is greater than 0 What are the hypotheses? Ho: Md is less than or equal to 0 Compute to 3 decimals). Individual Compute Sd (to 1 decimal). 1 2 3 4 Purchase Rating Before After 6 6 8 5 5 LO 5 8 3 Individual What is the p-value? The p-value is between 0.10 and 0.20 What is your decision? Cannot conclude seeing the commercial improves the mean potential to…arrow_forward
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