Chapter 11.2, Problem 30E

To determine

To find the magnitude of the vector $\text{v}=-\text{i}-\text{4j}+3\text{k}$ .

Answer to Problem 30E

  $\Vert \text{v}\Vert =\sqrt{26}$

Explanation of Solution

Given:

  $\text{v}=-\text{i}-\text{4j}+3\text{k}$

Concept used:

The magnitude of a vector $\text{u}=u_1\text{i}+u_2\text{j}+u_3\text{k}$ is,

  $\Vert \text{u}\Vert =\sqrt{u_1^2+u_2^2+u_3^2}$

Calculation:

  $\begin{array}{l}\text{v}=-\text{i}-\text{4j}+3\text{k}\\ \Rightarrow \Vert \text{v}\Vert =\sqrt{{\left(-1\right)}^2+{\left(-4\right)}^2+3^2}\\ =\sqrt{1+16+9}\\ =\sqrt{26}\end{array}$